Question

我在php代码中提交注释时出错，问题是第4行代码：

php_network_getaddresses：getaddrinfo失败：请求的名称是有效，但未找到所请求类型的数据。

有什么想法吗？

    <?php
if( $_POST )
{
  $con = mysql_connect('%', 'myuser', 'mypassword');

  if (!$con)
  {
    die('Could not connect: ' . mysql_error());
  }

  mysql_select_db("_mysite", $link);

  $users_name = $_POST['name'];
  $users_email = $_POST['email'];
  $users_website = $_POST['website'];
  $users_comment = $_POST['comment'];

  $users_name = mysql_real_escape_string($users_name);
  $users_email = mysql_real_escape_string($users_email);
  $users_website = mysql_real_escape_string($users_website);
  $users_comment = mysql_real_escape_string($users_comment);

  $articleid = $_GET['id'];
  if( ! is_numeric($articleid) )
    die('invalid article id');

  $query = "
  INSERT INTO `_mysite`.`comments` (`id`, `name`, `email`, `website`,
        `comment`, `timestamp`, `articleid`) VALUES (NULL, '$users_name',
        '$users_email', '$users_website', '$users_comment',
        CURRENT_TIMESTAMP, '$articleid');";

  mysql_query($query);

  echo "<h2>Thank you for your Comment!</h2>";

  mysql_close($con);
}
?>

Answer 1

%是mysql的通配符，当你将它用于你的用户所允许的主机时，它意味着'any host'，在你的情况下，它应该是localhost。< / p>

与您的问题无关，但如果您不了解它，则应考虑远离mysql_ deprecated的{{1}}函数，建议替换mysqli。

Answer 2

将$link替换为此行$con中的mysql_select_db("_mysite", $link);。这是我第一次看到任何服务器名称为%。我不太了解它。但是，您可以将%替换为localhost或port number或IP Address

<?php
if($_POST)
{
  $con = mysql_connect('localhost', 'myuser', 'mypassword');

  if (!$con) {
    die('Could not connect: ' . mysql_error());
  }

  mysql_select_db("_mysite", $con);

  $users_name = mysql_real_escape_string($_POST['name']);
  $users_email = mysql_real_escape_string($_POST['email']);
  $users_website = mysql_real_escape_string($_POST['website']);
  $users_comment = mysql_real_escape_string($_POST['comment']);

  $articleid = $_GET['id'];

  if(!is_numeric($articleid))
    die('invalid article id');

  $query = "INSERT INTO `_mysite`.`comments` (`id`, `name`, `email`, `website`,`comment`, `timestamp`, `articleid`) 
        VALUES (NULL, '$users_name','$users_email', '$users_website', '$users_comment',CURRENT_TIMESTAMP, '$articleid')";

  mysql_query($query);

  echo "<h2>Thank you for your Comment!</h2>";

  mysql_close($con);
}
?>

请停止使用mysql*个功能。这些扩展已在PHP 7中删除。了解PDO和MySQLi的准备好的语句。

使用MySqli

<?php
if($_POST)
{
  $con = mysqli_connect("localhost", "myuser", "mypassword", "_mysite");
  if (!$con) {
    die('Could not connect: ' . mysqli_connect_error());
  }

  $users_name = mysqli_real_escape_string($con, $_POST['name']);
  $users_email = mysqli_real_escape_string($con, $_POST['email']);
  $users_website = mysqli_real_escape_string($con, $_POST['website']);
  $users_comment = mysqli_real_escape_string($con, $_POST['comment']);

  $articleid = $_GET['id'];

  if(!is_numeric($articleid))
    die('invalid article id');

  $query = "INSERT INTO `_mysite`.`comments` (`id`, `name`, `email`, `website`,`comment`, `timestamp`, `articleid`) 
        VALUES (NULL, '$users_name','$users_email', '$users_website', '$users_comment',CURRENT_TIMESTAMP, '$articleid')";

  mysqli_query($con,$query)

  echo "<h2>Thank you for your Comment!</h2>";

  mysqli_close($con);
}
?>

有关详细信息，请参阅php_network_getaddresses: getaddrinfo failed:。

提交评论时出现php错误

2 个答案: