尝试通过同一用户捕获多个帐户的一部分,我们在用户登录时放置一个cookie。在登录期间,首先我们尝试读取先前的cookie并将其替换为新的cookie。读写的cookie存储在数据库中。当cookie没有被删除时,该系统可以是识别多账户的一部分。
使用递归函数搜索多个帐户时,内存不足。当不用作递归时,它可以工作,但有时用户有这么多帐户,我们只能通过对所有找到的帐户重复此功能来找到它们。 它重复此功能最多3次,但可以肯定的是,此函数必须运行,直到找不到多个帐户。
function xtest_getOtherNicks($dbh,$nick){
/**
Find all duplicate accounts, based on cookie
*/
$aOtherNicks = array();
$aCookies = db\ct_getCookies($dbh,$nick);
foreach($aCookies as $k => $aCookie){
$aFoundNicks = db\ct_getNick($dbh,$aCookies[$k]['cookiewaarde']);
if(count($aFoundNicks) > 0){
foreach($aFoundNicks as $key => $aFoundNick){
if(!in_array($aFoundNick['nick'],$aOtherNicks)){
$aOtherNicks[] = $aFoundNick['nick'];
//Recursive part
//$aMoreFoundNicks = xtest_getOtherNicks($dbh,$aFoundNick['nick']);
/**
if(count($aMoreFoundNicks)>0){
foreach($aMoreFoundNicks as $key => $aMoreFoundNick){
if(!in_array($aMoreFoundNick['nick'],$aOtherNicks)){
$aOtherNicks[] = $aMoreFoundNick['nick'];
}
}
} */
}
}
}
}
return $aOtherNicks;
}
我已经搜索了其他递归问题,但它们与我的不同。也许有可能更改SQL并让数据库完成工作,但我对此部分一无所知。
表:
CREATE TABLE IF NOT EXISTS `cookietest` (
`cookiewaarde` varchar(100) NOT NULL,
`nick` varchar(100) NOT NULL,
`datum` datetime NOT NULL,
`rw` enum('r','w') NOT NULL,
KEY `cookiewaarde` (`cookiewaarde`),
KEY `nick` (`nick`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1;
查询cookies:
$q = "SELECT
cookiewaarde
FROM
cookietest
WHERE
nick = '".sanitize($nick)."'";// will be converted to PDO
答案 0 :(得分:1)
您需要将$aOtherNicks
传递到递归范围。否则你不会破坏递归循环,因为它将与空数组进行比较(找到的值总是唯一的)。这个shuold工作:
function xtest_getOtherNicks($dbh, $nick, $aOtherNicks = array())
{
$aCookies = db\ct_getCookies($dbh, $nick);
foreach ($aCookies as $aCookie) {
$aFoundNicks = db\ct_getNick($dbh, $aCookie['cookiewaarde']);
foreach ($aFoundNicks as $aFoundNick) {
if (in_array($aFoundNick['nick'], $aOtherNicks)) { continue; }
$aOtherNicks[] = $aFoundNick['nick'];
$aOtherNicks = xtest_getOtherNicks($dbh, $aFoundNick['nick'], $aOtherNicks);
}
}
return $aOtherNicks;
}