Question

我想在我的应用程序中做一个简单的select语句。我要做的是返回与从列表视图接收的单词相关联的代码。当我运行代码时，我收到一个错误，指出列不存在。它说不存在的列实际上是传入语句的变量，而不是表中的任何列。任何帮助都会很棒

SQL声明

//gets recipe code given recipe name
public Cursor getCode(String name) throws SQLException
{
    return db.rawQuery("select recipe_code from recipes where recipe_name = " + name ,null);
}

将变量传递给语句

TextView txtProduct =（TextView）findViewById（R.id.recipeTitle）;

    Intent i = getIntent();
    // getting attached intent data
    String string = i.getStringExtra("recipe");
    // displaying selected product name
    txtProduct.setText(string);

    adapter.open();

    Cursor code = adapter.getCode(string);

表创建

//Recipe create statement
private static final String CREATE_TABLE_RECIPES = "CREATE TABLE "
        + RECIPE_TABLE + "("
        + KEY_ID + " INTEGER AUTO INCREMENT,"
        + KEY_CODE + " INTEGER PRIMARY KEY AUTOINCREMENT NOT NULL,"
        + KEY_RECIPE_NAME + " TEXT" + ")";

Answer 1

尝试使用这样的，

public Cursor getCode(String name) throws SQLException
{
    return db.rawQuery("select recipe_code from recipes where recipe_name = " + "'"+name+"'" ,null);
}

将您的变量保持在单引号内。

Android上没有变量名这样的列

1 个答案: