如何在R中的中间控制图的垂直线上绘制点

Question

需要创建一个如下所示的图表：

我几乎就在那里，只是错过了垂直绘制的各个点。

这里有数据：

q6 <- structure(list(x1 = c(0.0629, 0.063, 0.0628, 0.0634, 0.0619, 
0.0613, 0.063, 0.0628, 0.0623, 0.0631, 0.0635, 0.0623, 0.0635, 
0.0645, 0.0619, 0.0631, 0.0616, 0.063, 0.0636, 0.064, 0.0628, 
0.0615, 0.063, 0.0635, 0.0623), x2 = c(0.0636, 0.0631, 0.0631, 
0.063, 0.0628, 0.0629, 0.0639, 0.0627, 0.0626, 0.0631, 0.063, 
0.063, 0.0631, 0.064, 0.0644, 0.0627, 0.0623, 0.063, 0.0631, 
0.0635, 0.0625, 0.0625, 0.0632, 0.0629, 0.0629), x3 = c(0.064, 
0.0622, 0.0633, 0.0631, 0.063, 0.0634, 0.0625, 0.0622, 0.0633, 
0.0633, 0.0638, 0.063, 0.063, 0.0631, 0.0632, 0.063, 0.0631, 
0.0626, 0.0629, 0.0629, 0.0616, 0.0619, 0.063, 0.0635, 0.063), 
    x4 = c(0.0635, 0.0625, 0.0633, 0.0632, 0.0619, 0.0625, 0.0629, 
    0.0625, 0.063, 0.0631, 0.0635, 0.0627, 0.063, 0.064, 0.0622, 
    0.0628, 0.062, 0.0629, 0.0635, 0.0635, 0.062, 0.0619, 0.0631, 
    0.0631, 0.0626), x5 = c(0.064, 0.0627, 0.063, 0.0633, 0.0625, 
    0.0628, 0.0627, 0.0627, 0.0624, 0.063, 0.0633, 0.0629, 0.063, 
    0.0642, 0.0635, 0.0629, 0.0625, 0.0628, 0.0634, 0.0634, 0.0623, 
    0.0622, 0.063, 0.0633, 0.0628)), .Names = c("x1", "x2", "x3", 
"x4", "x5"), class = "data.frame", row.names = c(NA, -25L))

以下是代码：

range_span <- function(x) return(diff(range(x))) # function to calculate range
# q6 <- read.table(file="/Users/.../blah.csv",header=T,sep=",") #data
medians <- apply(q6,1,median) 
ranges <- apply(q6,1,range_span)
centre <- mean(medians) #grand median
Rtilde <- median(ranges) #median of ranges

plot(medians, type="b",xaxp=c(1, 25, 24),pch=19,xlab="Sample No.",ylab="Medians",main="Median Chart for Thickness of Metal Parts")

# code below draws the control limits 

action.limits<-c(centre+0.681*Rtilde,centre-0.681*Rtilde)
warn.limits<-c(centre+(2/3)*0.681*Rtilde,centre-(2/3)*0.681*Rtilde)

abline(h = centre, lty = 3, col = "black")  
v0 <-c("CL") 
mtext(side = 4, text = v0, at = centre, col = "black", las=2)

abline(h = warn.limits, lty = 3, col = "blue") 
v1 <-c("UWL","LWL") 
mtext(side = 4, text = v1, at = warn.limits, col = "blue", las=2) 

abline(h = action.limits, lty = 3, col = "black") 
v2 <-c("UCL","LCL") # the labels for action.limits
mtext(side = 4, text = v2, at = action.limits, col = "black", las=2)

我确定这是一个简单的解决方案，我根本没有经验，只是想通过在R中为图书作品制作图表来为自己设定挑战，但现在我和＃39 ; m开始没时间了。

• points()可以提供帮助吗？我需要R来识别q6中的每一行都是一个样本，我可以做points(q6,c(1:25))或类似的东西吗？

Answer 1

因此，您的数据中没有x坐标（1到25），这可能会使绘图变得困难。

None

下一步并非绝对必要，但它使事情更方便。我将把你的数据“融化”成长格式：

q6$x = 1:25

现在使用q6_long = reshape2::melt(q6, id.vars = "x") ## just showing what it looks like now head(q6_long) # x variable value # 1 1 x1 0.0629 # 2 2 x1 0.0630 # 3 3 x1 0.0628 # 4 4 x1 0.0634 # 5 5 x1 0.0619 # 6 6 x1 0.0613 函数添加点数很简单：

points