Question

我试图从函数返回集合对象Seq [String，String]但它没有用。这是我的方法，请帮我解决这个问题

def findAllBrandsseq:Seq[String,String] ={
              val brands =Seq[String,String]()


                 val conn = DB.getConnection()
                 try {
                    val stmt = conn.createStatement
                    val rs = stmt.executeQuery("SELECT * from m_brand")
                    while (rs.next()) {

                      brands:+(rs.getString("idbrand"),rs.getString("brandName"))
                    }
                } finally {
                    conn.close()
                }
                return brands
 }

它提供以下编译错误

从stdout读取：   D：\ PROJECTS \ test \ Project_VendorM6 \ app \ models \ Brand.scala：49：错误   Seq的类型参数数量应为1   D：\ PROJECTS \ test \ Project_VendorM6 \ app \ models \ Brand.scala：49：错误   Seq的类型参数的数量应该是1从stdout：def读取   findAllBrandsseq：Seq [String，String] = {                def findAllBrandsseq：Seq [String，String] = {从stdout读取：^                                     ^从标准输出读取：

D：\ PROJECTS \ test \ Project_VendorM6 \ app \ models \ Brand.scala：50：错误


方法适用的类型参数数量：[A]（元素：A *）Seq [A] in     class GenericCompanion     D：\ PROJECTS \ test \ Project_VendorM6 \ app \ models \ Brand.scala：50：错误     方法的类型参数数量适用：[A]（元素：A *）Seq [A] in     class GenericCompanion从stdout：val品牌中读取     = SeqString，字符串                   val brands = SeqString，String从stdout读取：^

需要从结果集创建Seq [String，String]

0 个答案: