Question

我希望得到以下结果：

set arr [0] = jan23,2016 ...... upto arr [6] = jan29,2016。

为此，我有以下代码：

// To get future or next 6 days from now or current date
NSCalendar * calendar = [NSCalendar autoupdatingCurrentCalendar];
NSDateComponents * datecomponents = [calendar components:NSCalendarUnitYear|NSCalendarUnitMonth|NSCalendarUnitDayfromDate:[NSDate date]];
for(int i=0;i<6;++i)
{
    NSDate * todaydate = [calendar dateFromComponents:datecomponents];
    NSLog(@"%@",todaydate);
    ++datecomponents.day;
    NSDateFormatter * dateformatter = [[NSDateFormatter alloc]init];
    [dateformatter setDateStyle:NSDateFormatterMediumStyle];
    NSString * convertedstring = [dateformatter stringFromDate:todaydate];
    NSLog(@“converteddate:%@",convertedstring);

为此，我收到了如下回复：

convertdate：2016年1月23日，类似于jan29,2016

然后我喜欢这个：

NSMutableString * newstring = [[NSMutableString alloc]init];
[newstring stringByAppendingString:convertedstring];
NSLog(@"%@",newstring);

也是这样：

    NSMutableArray * arrdata;
    arrdata = [[NSMutableArray alloc]init];
    [arrdata addObject:convertedstring];
    NSLog(@"%@",arrdata);
}

如何获得上述结果集。在字符串迭代之后如何将它们转换为数组。

Answer 1

在每次迭代重置时，必须在for循环之外声明和分配数组：

NSMutableArray * arrdata = [[NSMutableArray alloc]init];
NSCalendar * calendar = [NSCalendar autoupdatingCurrentCalendar];
NSDateComponents * datecomponents = [calendar components:NSCalendarUnitYear|NSCalendarUnitMonth|NSCalendarUnitDayfromDate:[NSDate date]];
for(int i=0;i<6;++i)

也没有必要这样做，因为你从来没有真正使用newstring：

NSMutableString * newstring = [[NSMutableString alloc]init];
[newstring stringByAppendingString:convertedstring];

Answer 2

以下是完整的答案：

NSCalendar *calendar = [NSCalendar autoupdatingCurrentCalendar];
NSDateComponents *datecomponents = [calendar components:NSCalendarUnitYear|NSCalendarUnitMonth|NSCalendarUnitDayfromDate:[NSDate date]];

NSDateFormatter *dateformatter = [[NSDateFormatter alloc]init];
[dateformatter setDateStyle:NSDateFormatterMediumStyle];

NSMutableArray *arr = [[NSMutableArray alloc] init];

for(int i = 0; i < 6; i++)
{
    NSDate * todaydate = [calendar dateFromComponents:datecomponents];
    NSLog(@"%@",todaydate);
    ++datecomponents.day;
    NSString *convertedstring = [dateformatter stringFromDate:todaydate];
    [arr addObject:convertedstring];
}

希望这有帮助！

如何将迭代的字符串值结果集转换为ios中的数组？

2 个答案: