Question

当有一个生产者和一个消费者时，我的代码很有效。但是如果我有不止一个消费者或生产者，他们就会得到相同的价值。（我已经看到很多答案，但是它们很复杂，有没有简单的解决方案）。

class QC {
int n;
boolean valueSet = false;

synchronized int get() {
    if(!valueSet) {
        try {
            wait();
        } catch (InterruptedException e) {
            System.out.println("InterruptedException caught");
        }
    }
    System.out.println("Got: " + n);
    valueSet = false;
    notify();
    return n;
}

synchronized void put(int n) {
    if(valueSet) {
        try {
            wait();
        } catch (InterruptedException e) {
            System.out.println("InterruptedException caught");
        }
    }
    this.n = n;
    valueSet = true;
    System.out.println("Put: " + n);
    notify();
}
}

生产者

class ProducerC implements Runnable {
QC q;

ProducerC(QC q) {
    this.q = q;
    new Thread(this, "Producer").start();
}

public void run() {
    int i = 0;
    while(true) {
        q.put(i++);
        try {
            Thread.sleep(1000);
        } catch(InterruptedException e) {
            System.out.println("Interrupted");
        }
    }
}
}

消费

class ConsumerC implements Runnable {
QC q;

ConsumerC(QC q) {
    this.q = q;
    new Thread(this, "Consumer").start();
}
@Override
public void run() {
    while(true) {
        q.get();
    }
}
}

主要

public class CorrectPC {
public static void main(String[] args) {
    QC q = new QC();
    new ProducerC(q);
    new ConsumerC(q);
    new ProducerC(q);
    System.out.println("Press Control-C to stop.");
}
}

Answer 1

我将使用Java提供的并发集合之一作为我的生产者和消费者之间的共同联系点。您可以从https://docs.oracle.com/javase/tutorial/essential/concurrency/collections.html了解更多信息。

Answer 2

试试这个。

    package com.sourcey.materiallogindemo;

import android.app.ProgressDialog;

import android.os.Bundle;
import android.support.v7.app.AppCompatActivity;
import android.util.Log;
import android.view.View;

import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;
import android.widget.Toast;



import butterknife.Bind;
import butterknife.ButterKnife;

public class SignupActivity extends AppCompatActivity {

    //URL to get JSON Array

    //JSON Node Names



    public String nurl;


    private static final String TAG = "SignupActivity";

    @Bind(R.id.input_name) EditText _nameText;
    @Bind(R.id.input_email) EditText _emailText;
    @Bind(R.id.input_tell) EditText _tellText;
    @Bind(R.id.input_password) EditText _passwordText;
    @Bind(R.id.btn_signup) Button _signupButton;
    @Bind(R.id.link_login) TextView _loginLink;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_signup);
        ButterKnife.bind(this);

        _signupButton.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                signup();
            }
        });

        _loginLink.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                // Finish the registration screen and return to the Login activity
                finish();
            }
        });
    }



    public void signup() {
        Log.d(TAG, "Signup");

        if (!validate()) {
            onSignupFailed();
            return;
        }

        _signupButton.setEnabled(false);

        final ProgressDialog progressDialog = new ProgressDialog(SignupActivity.this,
                R.style.AppTheme_Dark_Dialog);
        progressDialog.setIndeterminate(true);
        progressDialog.setMessage("در حال انجام عملیات...");
        progressDialog.show();

        String name = _nameText.getText().toString();
        String email = _emailText.getText().toString();
        String tell = _tellText.getText().toString();
        String password = _passwordText.getText().toString();

        // TODO: Implement your own signup logic here.

        nurl = "http://someurl/json/user.php?type=register&mobile="+tell+"&p="+password+"&email="+email+"&name="+name;

       //new JSONParse().execute();

        new android.os.Handler().postDelayed(
                new Runnable() {
                    public void run() {

                        onSignupSuccess();
                        progressDialog.dismiss();


                    }
                }, 3000);
    }


    public void onSignupSuccess() {
        _signupButton.setEnabled(true);
        setResult(RESULT_OK, null);
        finish();
    }

    public void onSignupFailed() {
        Toast.makeText(getBaseContext(), "Login failed", Toast.LENGTH_LONG).show();

        _signupButton.setEnabled(true);
    }

    public boolean validate() {
        boolean valid = true;

        String name = _nameText.getText().toString();
        String email = _emailText.getText().toString();
        String tell = _tellText.getText().toString();
        String password = _passwordText.getText().toString();

        if (name.isEmpty() || name.length() < 3) {
            _nameText.setError("at least 3 characters");
            valid = false;
        } else {
            _nameText.setError(null);
        }

        if (email.isEmpty() || !android.util.Patterns.EMAIL_ADDRESS.matcher(email).matches()) {
            _emailText.setError("enter a valid email address");
            valid = false;
        } else {
            _emailText.setError(null);
        }

        if (tell.isEmpty() || !android.util.Patterns.PHONE.matcher(tell).matches()) {
            _tellText.setError("enter a valid phone number");
            valid = false;
        } else {
            _tellText.setError(null);
        }

        if (password.isEmpty() || password.length() < 4 || password.length() > 10) {
            _passwordText.setError("between 4 and 10 alphanumeric characters");
            valid = false;
        } else {
            _passwordText.setError(null);
        }



        return valid;
    }













}

java中的多个Producer使用者

2 个答案: