我对python很陌生,我试图创建能够完成我手工完成的所有工作的循环。基本上创建所有行#' 变量,并从文件' game_catch.txt' 中分配特定的文本行。读到这样的东西:
Curving 10
Dodgeball 15
Keep Away 5
Kin-Ball 7
Prisoner Ball 21
Quidditch 30
Rundown (aka Pickle) 12
Yukigassen 18
Handball 25
(空格为Tabs,如果有任何区别的话)
然后创建另一个循环,在分割时将行' 变量的值分配给 str'#' 变量所有的间距。 (我无法修改该文件,因为在其他计算机中它将与我上面发布的文件相同,所以我必须执行此步骤)
然后,更重要的是因为这是我完全陷入困境的地方,为完成 str'#' 变量的所有细节工作做了一个循环进入体育词典可以拿起的东西,然后读作 {' Curving':10}
在这里,我提供了目前正在使用并尝试简化的代码:
file = open('game_catch.txt','r')
line1 = file.readline()
line2 = file.readline()
line3 = file.readline()
line4 = file.readline()
line5 = file.readline()
line6 = file.readline()
line7 = file.readline()
line8 = file.readline()
line9 = file.readline()
str1 = line1.split()
str2 = line2.split()
str3 = line3.split()
str4 = line4.split()
str5 = line5.split()
str6 = line6.split()
str7 = line7.split()
str8 = line8.split()
str9 = line9.split()
sports = {}
key = ''
for i in str1[0:-1] :
key += i + ' '
key = key[0:-1]
sports[key] = int(str1[-1])
很抱歉这篇长篇文章,我只想提供尽可能详细的信息。如果有更有效的方法,请随时告诉我。感谢
答案 0 :(得分:2)
您可以通过迭代文件,分割每一行,并将该生成器中的对发送到@RunWith(PowerMockRunner.class)
@PrepareForTest({ LocationAppDAO.class, BeanPropertyRowMapper.class })
public class CopyOfGeoLocationAppTest {
@Autowired
private ApplicationContext applicationContext;
@Test
@SuppressWarnings({ "unchecked" })
public void testJdbcTemplateforDbase() throws Exception {
// LocationAppDAO locationAppdao= new LocationAppDAO();
String queryWgs84 = "SELECT * FROM location_wgs84 where latitude=" + 0
+ " AND longitude=" + 0;
LocationAppDAO locationAppDaoMock= EasyMock.createMock(LocationAppDAO.class);
JdbcTemplate jdbcTemplateMock = EasyMock.createMock(JdbcTemplate.class);
BeanPropertyRowMapper<Location_wgs84> beanPropertyRowMapperMock = EasyMock
.createMock(BeanPropertyRowMapper.class);
EasyMock.replay(beanPropertyRowMapperMock);
// mocking location
Location_wgs84 location_wgs84mock = EasyMock
.createMock(Location_wgs84.class);
location_wgs84mock.setLatitude(0);
location_wgs84mock.setLongitude(0);
EasyMock.replay(location_wgs84mock);
PowerMock.expectNew(BeanPropertyRowMapper.class).andReturn(
beanPropertyRowMapperMock);
PowerMock.replayAll();
ArrayList<Location_wgs84> arrayList = new ArrayList<Location_wgs84>();
Location_wgs84 location1 = new Location_wgs84();
location1.setLatitude(1);
location1.setLongitude(1);
arrayList.add(location1);
Location_wgs84 location2 = new Location_wgs84();
location2.setLatitude(2);
location2.setLongitude(2);
arrayList.add(location2);
Location_wgs84 location3 = new Location_wgs84();
location3.setLatitude(3);
location3.setLongitude(3);
arrayList.add(location3);
EasyMock.expect(
jdbcTemplateMock.query(queryWgs84, beanPropertyRowMapperMock))
.andStubAnswer(new IAnswer<List<Location_wgs84>>() {
@Override
public List<Location_wgs84> answer() throws Throwable {
return arrayList;
};
});
EasyMock.replay(jdbcTemplateMock);
EasyMock.expect(
locationAppDaoMock.location_wgs84Query(0,0))
.andStubAnswer(new IAnswer<List<Location_wgs84>>() {
@Override
public List<Location_wgs84> answer() throws Throwable {
return arrayList;
};
});
EasyMock.replay(locationAppDaoMock);
LocationAppDAO locationAppdao= new LocationAppDAO();
ReflectionTestUtils.setField(locationAppdao, "jdbcTemplate", jdbcTemplateMock);
List<Location_wgs84> arrayListResult = locationAppdao.location_wgs84Query(0, 0);
assertEquals(3.0, arrayListResult.get(2).getLatitude(), 0);
EasyMock.verify(jdbcTemplateMock);
}
}
来获得基本结构(将分数保持为字符串):
dict()
您可以通过创建生成器来分割每一行,然后解压每一行并使用with open('game_catch.txt') as f:
d = dict(line.rsplit(maxsplit=1) for line in f)
函数来将分数转换为整数:
int()
您可以使用文字理解语法而不是with open('game_catch.txt') as f:
d = dict((name, int(score)) for name, score in (line.rsplit(maxsplit=1) for line in f))
函数:
dict()
当然,最重要的部分是查看教程,以便您可以了解这些代码片段的作用并理解解释。循环和数据结构尤为重要。
答案 1 :(得分:1)
考虑到一些体育名称由多个单词组成,以下内容将把你的txt文件变成字典:
lines = [line.rstrip('\n').split() for line in open('C:/Users/Simon/Desktop/test.txt')]
sports = {}
for el in lines:
number = el.pop()
curItem = ' '.join(el)
sports[curItem] = int(number)
print sports
这将是这样的:
{'Curving': 10, 'Keep Away': 5, 'Dodgeball': 15}
答案 2 :(得分:0)
file = 'game_catch.txt'
sports = {}
with open(file) as f:
for line in f:
parts = line.split()
sports[parts[0]] = int(parts[-1])
希望这会有所帮助。
答案 3 :(得分:0)
示例
trans_dict = {&#39; one&#39;:&#39; wahed&#39;,&#39; two&#39;:&#39; itnen&#39;,&#39; three&#39; :&#39;塔拉塔&#39;}
print "ITER ITEMS", trans_dict.iteritems()
for key, val in trans_dict.iteritems():
print "KEY", key
print "VAL", val