在第一个索引中包含字符串的变体数组 - 用双重类型不匹配覆盖它

时间:2016-01-21 18:52:46

标签: arrays excel vba excel-vba

我有一个变体数组,如下所示:

“狗” “猫” “马”

我想用

覆盖这些值
1.01
2.02
3.03

代码:

sumHolder = loanSums(x)
If sumHolder = "N/A" Then
    sumHolder = "0"
End If
loanSums(x) = vbNull
loanSums(x) = sumHolder + trimmedRange(i, trimmedRngCols.paymentAmt)

我试图在字符串上分配双精度,但我得到的是类型不匹配。关于如何做到这一点的任何想法

1 个答案:

答案 0 :(得分:6)

你做得不对。

一维变体数组:

Dim a As Long, vals As Variant

vals = Array("dog", "cat", "horse")

For a = LBound(vals) To UBound(vals)
    Debug.Print vals(a)
    vals(a) = CDbl(a + 1 + (a + 1) / 100)
Next a

For a = LBound(vals) To UBound(vals)
    Debug.Print vals(a)
Next a

立即窗口的结果:

dog
cat
horse
 1.01 
 2.02 
 3.03 

二维变体数组:

dim a as long, vals as variant, tmp as variant

vals = range("A2:E4").value2

debug.print lbound(vals, 1) & ":" & ubound(vals, 1)  '1:3, 3 'rows' in array
debug.print lbound(vals, 2) & ":" & ubound(vals, 2)  '1:5, 5 'columns' in array

for a = lbound(vals, 1) to ubound(vals, 1)
    debug.print vals(a, 1) & " - " & vals(a, 3)
    tmp = vals(a, 1)
    vals(a, 1) = vals(a, 3)
    vals(a, 3) = tmp
next a

for a = lbound(vals, 1) to ubound(vals, 1)
    debug.print vals(a, 1) & " - " & vals(a, 3)
next a

range("A2").resize(ubound(vals, 1), ubound(vals, 2)) = vals

立即窗口和工作表中的结果:

1:3
1:5
dog - 1.01
cat - 2.02
horse - 3.03
1.01 - dog
2.02 - cat
3.03 - horse
处理 之后

variant_array_substitution_before variant_array_substitution_after

我已经包含了一些前后图像,以便您可以通过左对齐(文本)和右对齐(数字)清楚地看到交换文本的变量编号的单元格值,反之亦然应该不是问题。您的'类型不匹配'必须是值转移以外的其他内容。