如何在spring security authenticated登录中获取用户输入的用户名和密码值

时间:2016-01-21 18:32:31

标签: java spring security spring-mvc spring-security

我在我的应用程序中使用Spring MVC,登录通过spring security进行身份验证。我的UserServiceImpl.java课程中有以下两种方法, public UserDetails loadUserByUsername(String userName)throws UsernameNotFoundException,DataAccessException         {

        ApplicationTO applicationTO = null;
        try
            {
                applicationTO = applicationService.getApplicationTO(adminDomainName);
            }
        catch (ApplicationPropertyException e)
            {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
        UserTO userTO = getUserTO(applicationTO.getApplicationId(), userName);
        if (userTO == null)
            {
                throw new UsernameNotFoundException("user not found");
            }
        httpSession.setAttribute("userTO", userTO);
        return buildUserFromUserEntity(userTO);
    }


User buildUserFromUserEntity(UserTO userTO)
            {
                String username = userTO.getUsername();
                String password = userTO.getPassword();
                int userId = userTO.getUserId();
                int applicationId = userTO.getApplicationId();
                boolean enabled = userTO.isEnabled();
                boolean accountNonExpired = true;
                boolean credentialsNonExpired = true;
                boolean accountNonLocked = true;
                User user = new User(username, password, enabled, accountNonExpired, credentialsNonExpired, accountNonLocked, getAuthority(applicationId, userId));
                return user;
            }

我对Spring比较陌生,对弹簧安全部分不太了解。在我的spring-security.xml文件中,我有以下内容,

<form-login login-page="/login" default-target-url="/module/user-home/welcome"
    authentication-failure-url="/login?error" username-parameter="username"
    password-parameter="password" />
<logout logout-success-url="/login?logout" />

<beans:bean id="daoAuthenticationProvider"
 class="org.springframework.security.authentication.dao.DaoAuthenticationProvider">
  <beans:property name="userDetailsService" ref="userDetailsService"/>
</beans:bean>

<beans:bean id="authenticationManager"
    class="org.springframework.security.authentication.ProviderManager">
  <beans:property name="providers">
    <beans:list>
      <beans:ref local="daoAuthenticationProvider" />
    </beans:list>
  </beans:property>
</beans:bean>

我的登录表单的操作设置如下:

<form id="loginForm" class="form-horizontal" role="form" name='loginForm' action="${rc.getContextPath()}/j_spring_security_check" method='POST'>

现在,我尝试在password方法内或向loadUserByUsername添加新方法,以获取用户在登录表单中输入的UserServiceImpl.java的值类。

在保存密码之前,我使用以下内容加密密码。 What API and algorithm to be used to encrypt and decrypt a password using java

因此,在登录期间,Spring安全性会将用户输入的密码与数据库中的加密密码进行比较,并且登录失败。但是根据上面链接中建议的实现,有一种方法可以比较密码和加密密码以检查它们是否相同。只有当我可以访问用户输入的密码时才可以这样做。这就是我试图让用户输入密码的原因。

2 个答案:

答案 0 :(得分:7)

如果需要,您可以创建自己的AuthenticationProvider

public class CustomAuthenticationProvider implements AuthenticationProvider{

    private UserDetailsService service;

    @Override
    public Authentication authenticate(Authentication authentication) throws AuthenticationException {
        UsernamePasswordAuthenticationToken token = (UsernamePasswordAuthenticationToken) authentication;
        String username = token.getName();
        String password = token.getCredentials(); // retrieve the password 
        // do something here

        // if ok then return the authentication
        return new UsernamePasswordAuthenticationToken(username, password, authorities);
    }
}

并将其插入您的安全配置

<beans:bean id="customAuthenticationProvider"
 class="com.xxx.CustomAuthenticationProvider">
  <beans:property name="userDetailsService" ref="userDetailsService"/>
</beans:bean>

<beans:bean id="authenticationManager"
    class="org.springframework.security.authentication.ProviderManager">
  <beans:property name="providers">
    <beans:list>
      <beans:ref local="customAuthenticationProvider" />
    </beans:list>
  </beans:property>
</beans:bean>

答案 1 :(得分:4)

正如MangEngkus在回答中建议的那样,您可以实施自己的自定义 AuthenticationProvider ,但根据您的说明,我认为您不需要这样做。

您不需要在spring-security中实现自己的密码散列机制。你只需要从spring本身定义BCryptPasswordEncoder

要么使用默认方式:

<authentication-manager>
  <authentication-provider>
    <password-encoder hash="bcrypt" />
  </authentication-provider>
</authentication-manager>

或者创建自己的bean并将其提供给默认提供者:

<authentication-manager>
  <authentication-provider>
    <password-encoder ref="encoder" />
  </authentication-provider>
</authentication-manager>

<beans:bean id="encoder" 
  class="org.springframework.security.crypto.bcrypt.BCryptPasswordEncoder">
    <beans:constructor-arg name="strength" value="15" />
</beans:bean>

但对你而言,这就是::))

<beans:bean id="daoAuthenticationProvider" class="org.springframework.security.authentication.dao.DaoAuthenticationProvider">
  <beans:property name="userDetailsService" ref="userDetailsService"/>
  <beans:property name="passwordEncoder" ref="encoder" />
</beans:bean>

<bean id="encoder" class="org.springframework.security.crypto.bcrypt.BCryptPasswordEncoder"/>