Question

我想检查用户是否给了脚本任何参数，如果是这种情况，脚本应该关闭。

if [ $@ = "" ]; then
    exit
fi

无效。

Answer 1

你可以这样试试，

<script type="text/javasctipt">var arr1 = [{"id":2,"student_name":"LSa"},{"id":3,"student_name":"Liu Sa"},{"id":77,"student_name":"Liu Sa"}];
var arr2 = [{"id":2,"student_name":"A"},{"id":3,"student_name":"L"},{"id":4,"student_name":"B"},{"id":55,"student_name":"C"},{"id":25,"student_name":"D"},{"id":23,"student_name":"E"},{"id":89,"student_name":"F"}];

arr1.forEach(function(value1) {
    arr2.forEach(function(value2) {
        if (value1.id === value2.id ) {
            document.getElementById('list').innerHTML += (value2.student_name + " -- true, <br/>");
        }else{
            document.getElementById('list').innerHTML += (value2.student_name +" -- false, <br/>");
        }
    });
});

//Expected result : A-true,L-true,B-false,C-false,D-false,E-false,F-false</script>
<div id="list"></div>

我如何检查是否没有给出参数

1 个答案: