Question

我有程序代码，它工作正常，除了几行，程序必须找到最小的值并打印出来。

我有字符串字段/框“fieldEvidence.WorkingYears”。用户必须写0到40之间的数字。用户可以放置最多10个值或更少（十个人）。程序必须在控制台中写出“fieldEvidence.WorkingYears”中最低的walue 如果值相同（比如2次'30'），程序必须同时写两个。

我现在有一些代码，但它没有以正确的方式工作，我应该改变什么？

    static void WorkingAge(Evidence[] fieldEvidence)
    {
        int maxYears = 40;
        int counter = 0;

        for (int i = 0; i < fieldEvidence.Length; i++)
        {
            if (maxYears > fieldEvidence[i].WorkingYears)
            {
                maxYears = fieldEvidence[i].WorkingYears;
            }
        }
        //10 times for loop
        for (int i = 0; i < 10; i++)
        {
            if (maxYears == fieldEvidence[i].WorkingYears)
                counter++;
        }

        //if there is more than just one with the same value
        if (counter > 1)
        {
            for (int i = 0; i < fieldEvidence.Length; i++)
            {
                if (maxYears == fieldEvidence[i].WorkingYears)
                {
                    Console.WriteLine("Working years:{0}, fieldEvidence[i].WorkingYears);
                }
            }
        }
        else
        {
            for (int i = 0; i < fieldEvidence.Length; i++)
            {
                if (maxYears == fieldEvidence[i].WorkingYears)
                {
                    Console.WriteLine("Working years:{0}, fieldEvidence[i].WorkingYears);
                }
            }
        }
    }

实施例用户输入：40,30,23,14,34 产出：工作年限：14

示例2 用户输入：40,23,14,14,34 产出：工作年限：14,14

Answer 1

我建议您使用LINQ - 非常简单：

var example = new[]{40,30,23,14,34}.Select(year => new Evidence(year)).ToList();
var lowestVal = example.Min(x => x.WorkingYears);
var result = example.Where(x => x.WorkingYears == lowestVal)
                    .Select(x => x.WorkingYears);
Console.WriteLine("Working years: " + string.Join(", ", result));

Answer 2

static void WorkingAge(Evidence[] fieldEvidence)
{
    // make a counter for the number of equal min's found
    int counter = 1;

    // start with min equal to the first age in the array
    int min = fieldEvidence[0];

    // loop through array to find a possible new min
    for (int i = 1; i < fieldEvidence.Length; i++) {
        // if value < min, set min to this value and reset counter to 1
        if (fieldEvidence[i].WorkingYears < min) {
            min = fieldEvidence[i].WorkingYears;
            counter = 1;
        }
        // if value equal to min, increase counter
        else if (fieldEvidence[i].WorkingYears == min)
            counter++;
    }

    // create your output string starting with the min
    string output = min.ToString();
    // loop "counter" times to add multiple identical mins to string
    for (int i = 1; i < counter; i++) {
        output = output + ", " + min;
    } 

    // output the string
    Console.WriteLine("Working years: " + output);

}

C＃在框/字段中找到最小的数量

2 个答案: