如何构造Immutable.Record的子类？

Question

class Event extends Immutable.Record {
  constructor(text) {
    super({text: text, timestamp: Date.now()});
  }
}

调用new Event()似乎返回一个constuctor函数：

new Event('started').toString()

  

“function Record（values）{if（values instanceof RecordType）{return   值;}

     

if（！（此实例为RecordType））{return new RecordType（values）;}

     

if（！hasInitialized）{hasInitialized = true; VAR   键= Object.keys（defaultValues）; setProps（RecordTypePrototype，密钥）;   RecordTypePrototype.size = keys.length; RecordTypePrototype._name =名称;   RecordTypePrototype._keys =键;   RecordTypePrototype._defaultValues = defaultValues;}

     

this._map =地图（值）;}“

调用函数返回预期的输出：

new Event('started')().toString()

  

“记录{”文字“：”已开始“，”时间戳“：1453374580203}”

我做错了什么？

Answer 1

Immutable.Record＆＃34; Creates a new Class which produces Record instances。＆＃34;，换句话说，它是一个函数，你传递允许的键并返回一个你可以扩展的类;

class Event extends Immutable.Record({text:'', timestamp:''}) {
  constructor(text) {
    super({text: text, timestamp: Date.now()});
  }
}

> new Event('started').toString()
Event { "text": "started", "timestamp": 1453376445769 }