带有数组数据的jqgrid中的分页问题

时间:2010-08-16 09:30:04

标签: javascript jquery json jqgrid pagination

我在jqgrid中遇到了具有18条记录的数组数据的分页问题,​​但是即使我指定了分页,记录也没有显示在页面中:true,pager:jQuery('#pager1')。你能帮我实现分页而不是滚动。

<script type="text/javascript">
 jQuery("#list4").jqGrid({
 datatype: "clientSide",
 height: 200,
    colNames:['Inv No','Date', 'Client', 'Amount','Tax','Total','Notes'],
    colModel:[
    {name:'id',index:'id', width:60, sorttype:"int"},
    {name:'invdate',index:'invdate', width:90, sorttype:"date"},
    {name:'name',index:'name', width:100},
    {name:'amount',index:'amount', width:80, align:"right",sorttype:"float"},
    {name:'tax',index:'tax', width:80, align:"right",sorttype:"float"},
    {name:'total',index:'total', width:80,align:"right",sorttype:"float"},
    {name:'note',index:'note', width:150, sortable:false}
    ],
    multiselect: true,
 pagination:true,
  pager:jQuery('#pager1'), 
 rowNum: 10,
 rowList: [5, 10, 20, 50],
 sortname: 'id',   
 sortorder: 'asc',
 viewrecords: true,
 page: 1,
 loadonce: true,  
 totalpages: 2,   
 totalrecords:18,     
 showpage:true,   
 imgpath: "/themes/default/images",         
 caption: "Manipulating Array Data"
 });
 var mydata = [
 {id:"1",invdate:"2007-10-01",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"},
 {id:"2",invdate:"2007-10-02",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"},
 {id:"3",invdate:"2007-09-01",name:"test3",note:"note3",amount:"400.00",tax:"30.00",total:"430.00"},
 {id:"4",invdate:"2007-10-04",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"},
 {id:"5",invdate:"2007-10-05",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"},
 {id:"6",invdate:"2007-09-06",name:"test3",note:"note3",amount:"400.00",tax:"30.00",total:"430.00"},
 {id:"7",invdate:"2007-10-04",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"},
 {id:"8",invdate:"2007-10-03",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"},
 {id:"9",invdate:"2007-09-01",name:"test3",note:"note3",amount:"400.00",tax:"30.00",total:"430.00"},
 {id:"10",invdate:"2007-10-01",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"},
 {id:"11",invdate:"2007-10-02",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"},
 {id:"12",invdate:"2007-09-01",name:"test3",note:"note3",amount:"400.00",tax:"30.00",total:"430.00"},
 {id:"13",invdate:"2007-10-04",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"},
 {id:"14",invdate:"2007-10-05",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"},
 {id:"15",invdate:"2007-09-06",name:"test3",note:"note3",amount:"400.00",tax:"30.00",total:"430.00"},
 {id:"16",invdate:"2007-10-04",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"},
 {id:"17",invdate:"2007-10-03",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"},
 {id:"18",invdate:"2007-09-01",name:"test3",note:"note3",amount:"400.00",tax:"30.00",total:"430.00"},

 ];
 for(var i=0;i<=mydata.length;i++)   
 jQuery("#list4").addRowData(i+1,mydata[i]);

2 个答案:

答案 0 :(得分:10)

您的主要问题是在添加大量行后应重置rowNum。这条线

jQuery("#list4").setGridParam({ rowNum: 10 }).trigger("reloadGrid");
代码末尾的

将解决问题。我建议你添加一行

jQuery("#list4").jqGrid('navGrid','#pager1',{edit:false,add:false,del:false});

直接定义jqGrid之后。然后,您不仅可以进行数据分页,还可以进行数据过滤(搜索)和刷新(重置过滤器)。

更多小言论:

  • mydata数组的定义中,您应该删除','在']'之前。
  • 在for循环中
  • ,您应该使用i<mydata.length而不是i<=mydata.length
  • 你应该从jqGrid的定义中删除以下参数,这些参数不存在(如pagination)或在上下文中没有意义(如loadonce: true):pagination,{{ 1}},pageloadoncetotalpagestotalrecordsshowpage

如果您根据imgpath参数构建jqGrid,或者同时设置data: myData的所有数据,则会收到最佳结果(请参阅http://www.trirand.com/jqgridwiki/doku.php?id=wiki:retrieving_data#array_datamydata方法的说明)。

答案 1 :(得分:1)

Oleg是对的。 添加jQuery(“#list4”)。setGridParam({rowNum:10})。trigger(“reloadGrid”); 的工作原理。

虽然如果设置了 formatter 属性,但未定义rowObject值(如果使用它们),它可能不起作用

因此,请确保在格式化程序方法中始终检查其可用性。

e.g。

function getFormattedFileName(cellvalue, options, rowObject) {

        if(!rowObject.fileName) {// this is due to ...trigger("reloadGrid");
            return cellvalue; // the value is already formatted, let's just return it
        }
 return rowObject.fileName.trim();
}