我需要通过"与其余"的联系人对以下数据表进行排序。列,但仅适用于支架之前的数字。
这是我的代码:
var oTable = $('#customers-list').dataTable({});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script src="https://cdn.datatables.net/1.10.10/js/jquery.dataTables.min.js"></script>
<table id="customers-list" class="table table-striped table-bordered table-hover">
<thead>
<tr>
<th>Name</th>
<th>Total
<br>contacts</th>
<th>Contacts with
<br>the remaining</th>
</tr>
</thead>
<tbody>
<tr>
<td>Test1</td>
<td class="text-center">11</td>
<td class="text-center">7 (63.64%)</td>
</tr>
<tr>
<td>Test2</td>
<td class="text-center">25</td>
<td class="text-center">14 (56%)</td>
</tr>
<tr>
<td>Test3</td>
<td class="text-center">24</td>
<td class="text-center">24 (100%)</td>
</tr>
<tr>
<td>Test4</td>
<td class="text-center">24</td>
<td class="text-center">3 (12.5%)</td>
</tr>
<tr>
<td>Test5</td>
<td class="text-center">24</td>
<td class="text-center">20 (83.33%)</td>
</tr>
<tr>
<td>Test6</td>
<td class="text-center">24</td>
<td class="text-center">24 (100%)</td>
</tr>
<tr>
<td>Test7</td>
<td class="text-center">24</td>
<td class="text-center">22 (91.67%)</td>
</tr>
<tr>
<td>Test8</td>
<td class="text-center">24</td>
<td class="text-center">22 (91.67%)</td>
</tr>
<tr>
<td>Test9</td>
<td class="text-center">24</td>
<td class="text-center">24 (100%)</td>
</tr>
<tr>
<td>Test10</td>
<td class="text-center">24</td>
<td class="text-center">24 (100%)</td>
</tr>
<tr>
<td>Test11</td>
<td class="text-center">24</td>
<td class="text-center">24 (100%)</td>
</tr>
<tr>
<td>Test12</td>
<td class="text-center">0</td>
<td class="text-center">0 (0%)</td>
</tr>
<tr>
<td>Test13</td>
<td class="text-center">24</td>
<td class="text-center">24 (100%)</td>
</tr>
</tbody>
</table>
&#13;
答案 0 :(得分:3)
数据顺序和数据排序可以执行此操作
you can do like this
<td class="text-center" data-order="14">14 (56%)</td>
了解更多
https://datatables.net/examples/advanced_init/html5-data-attributes.html
答案 1 :(得分:0)
请参阅此DataTable Example。
您需要在表初始化时添加排序特征。 JSFiddle
$('#example').DataTable( {
"order": [[ 3, "desc" ]]
} );
答案 2 :(得分:0)
我找到了解决方案:
var oTable = $('#customers-list').dataTable({
{
'sType': 'num-html',
'aTargets': [2]
}
});
$.extend($.fn.dataTableExt.oSort, {
"num-html-pre": function(a) {
var x = String(a).replace(/<[\s\S]*?>/g, "");
return parseFloat(x);
},
"num-html-asc": function(a, b) {
return ((a < b) ? -1 : ((a > b) ? 1 : 0));
},
"num-html-desc": function(a, b) {
return ((a < b) ? 1 : ((a > b) ? -1 : 0));
}
});