Question

我通过从数据库获取数据在php中创建最新的产品列表。我想从我的数据库中回复18个最新产品。我正在为每个项目提供外部html，这些项目将针对具有不同数据的所有产品进行回显。以下是获取最新产品的查询

$query = mysql_query("SELECT * FROM devices ORDER BY id DESC LIMIT 3") or die(mysql_error());
while($row=mysql_fetch_array($query))

这是html：

<div class="col-xs-6 col-sm-4 col-md-3 col-lg-2 nopadding">  

            <div class="device_box">                        


                <a title="'.$row['name'].'" href="'.$row['link'].'"><img class="img-responsive" alt="'.$row['name'].'" title="'.$row['name'].'" src="'.$row['img'].'" /></a>


                <span>

                <a title="'.$row['name'].'" href="'.$row['link'].'">'.$row['name'].'</a>

                <br /><div class="price_small">'.$row['price'].'</div>
                </span>

            </div>              

        </div>

我希望使用foreach循环回显18个产品。我尝试使用foreach但它显示错误。

Warning: Invalid argument supplied for foreach()

任何帮助都会得到满足。感谢。

Answer 1

试试这个

$sql = "sql query";
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
// output data of each row
while($row = mysqli_fetch_row($result)) {
  echo '<div class="col-xs-6 col-sm-4 col-md-3 col-lg-2 nopadding">
        <div class="device_box">
            <a title="'.$row['name'].'" href="'.$row['link'].'"><img class="img-responsive" alt="'.$row['name'].'" title="'.$row['name'].'" src="'.$row['img'].'" /></a>
            <span>
            <a title="'.$row['name'].'" href="'.$row['link'].'">'.$row['name'].'</a>
            <br /><div class="price_small">'.$row['price'].'</div>
            </span>
        </div>
    </div>';
}

Answer 2

不要将$ row分配给$ data，如$ data [] = $ row。虽然循环可以排序你的问题，不要去foreach。使用此：

 $query = mysql_query("SELECT * FROM devices ORDER BY id DESC LIMIT 3") or die(mysql_error());

    while($row=mysql_fetch_array($query)){ ?>

<div class="col-xs-6 col-sm-4 col-md-3 col-lg-2 nopadding">  

            <div class="device_box">                        


                <a title="<?php echo $row['name'] ?>" href="<?php echo $row['link'] ?>"><img class="img-responsive" alt="<?php echo $row['name'] ?>" title="<?php echo $row['name'] ?>" src="<?php echo $row['img'] ?>" /></a>


                <span>

                <a title="<?php echo $row['name'] ?>" href="<?php echo $row['link'] ?>"><?php echo $row['name'] ?></a>

                <br /><div class="price_small"><?php echo $row['price'] ?></div>
                </span>

            </div>              

        </div>


   <?php  } ?>

Answer 3

试试这个

    <? 
$sql = "YOUR QUERY HERE";
$result = mysql_query($conn, $sql);
//if (mysql_num_rows($result) > 0) {
// output data of each row
$data = array();
while($row = mysql_fetch_assoc($result)) {
    $data[] = $row;
}
foreach($data as $key=>$val) { ?>
  <div class="col-xs-6 col-sm-4 col-md-3 col-lg-2 nopadding">
        <div class="device_box">
            <a title="<?php echo $val['name']; ?>" href="<?php echo $val['link'];?>"><img class="img-responsive" alt="<?php echo $val['name'];?>" title="<?php echo $val['name'];?>" src="<?php echo $val['img'];?>" /></a>
            <span>
            <a title="<?php echo $val['name'];?>" href="<?php echo $val['link'];?>"><?php echo $val['name'];?></a>
            <br /><div class="price_small"><?php echo $val['price'];?></div>
            </span>
        </div>
    </div>';
<? } ?>

在mysql php中显示多个产品foreach行

3 个答案: