Question

好吧，我的表格有点问题，我试过很多方法都没用当我点击SEND时，它会给我这个错误

TokenMismatchException in VerifyCsrfToken.php line 53:

好的，我得到了这个，我把<input type="hidden" name="_token" value="{{ csrf_token() }}">

<{1>}

下的

然后我收到了这个错误

<form action="" method="post" class="landing-form">

这是我的表单代码

MethodNotAllowedHttpException in RouteCollection.php line 219:

这也是我的class.FormValidation.js

<!DOCTYPE html>
<html>
  <head>
    <meta charset="utf-8" />
    <title>landin page</title>
    <script src="http://code.jquery.com/jquery-latest.min.js" type="text/javascript"></script> 
    <script type="text/javascript" href="{{asset('js/class.FormValidation.js')}}"></script>
    <script type="text/javascript" href="{{asset('js/landin_validation.js')}}"></script>
    <link rel="stylesheet" type="text/css" href="{{asset ('js/style.css')}}"/>
  </head>
  <body>
    <div class="page-wrapper">
      <div class="header-wrapper">
        <div class="header-content">Company Logo Here</div>
      </div>
      <div class="content">
        <h1>Advertising Header Goes Here!</h1>
        <p>
          There are many variations of passages of Lorem Ipsum available,<br/> 
          but the majority have suffered alteration in some form, by injected humour, <br/> 
          or randomised words which don't look even slightly believable. <br/> 
          If you are going to use a passage of Lorem Ipsum, <br/> 
          you need to be sure there isn't anything embarrassing hidden in the middle of text. <br/> 
          All the Lorem Ipsum generators on the Internet tend to repeat predefined chunks as necessary, <br/> 
          making this the first true generator on the Internet. It uses a dictionary of over 200 Latin words, <br/> 
          combined with a handful of model sentence structures, to generate Lorem Ipsum which looks reasonable. <br/> 
          The generated Lorem Ipsum is therefore always free from repetition, injected humour,<br/>  
          or non-characteristic words etc.
        </p>
        <div class="form-wrapper">
          <form action="" method="post" class="landing-form">    
              <input type="hidden" name="_token" value="{{ csrf_token() }}">
            <label>Fill your details here - </label><br/><br/>
            <input placeholder="Full name:" type="text" name="name" class="field-name" />
            <input placeholder="Email:" type="text" name="email" class="field-email" />
            <input placeholder="Phone Number:" type="text" name="phone" class="field-phone" />
            <input type="submit" name="submit" value="Send" />
          </form>
        </div>
      </div>
      <div class="footer">2014 &copy; My Compay Name</div>
    </div>
  </body>
</html>

这是路线：

function FormValidation(){

  this.nameReg = [
    /^([a-zA-Z\s]+){2,255}$/
  ];

  this.emailReg = [
    /^[_a-z0-9-]+(.[_a-z0-9-]+)*@[a-z0-9-]+(.[a-z0-9-]+)*(.[a-z]{2,3})$/
  ];

  this.phoneReg = [
    /^[0-9]{3}-[0-9]{3}-[0-9]{4}$/i,
    /^[0-9]{3}.[0-9]{3}.[0-9]{4}$/i,
    /^\([0-9]{3}\)-[0-9]{3}-[0-9]{4}$/i,
    /^[0-9]{9,10}$/i
  ];

  this.testName = function( nameInput ){

    return this.inputCheck(this.nameReg, nameInput);

  };

  this.testEmail = function( emailInput ){

    return this.inputCheck(this.emailReg, emailInput);

  };

  this.testPhone = function( phoneInput ){

    return this.inputCheck(this.phoneReg, phoneInput);

  };

  this.inputCheck = function( regArray, inputData ){

    var valid = false;

    $.each( regArray, function( key, val ){

      if( val.test( inputData ) ){

        valid = true;

      }

    });

    return valid;

  };

}

这是pagescontroller：

Route::get('contact', 'PagesController@contact');

我真的希望你帮助我，谢谢:)。

Answer 1

看起来您的联系路线的POST请求没有可用的路由。正如你所说：

Route::get('contact', 'PagesController@contact');

是您表单的路由，但Laravel无法使用您从表单发送的POST请求验证GET请求。因此，您需要第二个路径（和方法）来处理POST请求：

Route::post('contact', 'PagesController@postContact');

你仍然需要在PagesController上使用postContact（）方法来处理post请求。

P.S。你也可以用这个：

{!! csrf_field() !!}

这会将令牌字段的HTML代码添加到表单中，而无需键入任何隐藏字段。

P.S。你也可以用这个：

Route::any('/contact', 'PagesController@contact');

但是这需要你在contact（）方法中执行逻辑（从GET请求中分离POST）。

VerifyCsrfToken.php第53行中的TokenMismatchException：

1 个答案: