Question

在运行关于摇滚，纸张和剪刀的小脚本时，我得到了这个错误。这是我的代码，它在第二个elif语句中失败了，你能弄清楚为什么吗？

function compare () {
    if [ "$userChoice" == "$computerChoice" ]
       then echo "Empate!"
    elif [ "$userChoice" == "piedra" ]
        if [ "$computerChoice" == "tijeras" ]
            then echo "La piedra gana"
        else
            echo "El papel gana"
        fi
    elif [ "$userChoice" == "papel" ]
        if [ "$computerChoice" == "piedra" ]
            then echo "El papel gana"
        else
            echo "Las tijeras ganan"
        fi
    fi
}
compare $userChoice $computerChoice

错误消息是：

myscript: line 10: syntax error near unexpected token `elif'
myscript: line 10: `    elif [ "$userChoice" == "papel" ]'

Answer 1

在elif之后你也需要then。

Answer 2

你忘记了一对夫妇＆＃34;然后＆＃34;声明。永远记住的好方法是添加＆＃34;然后＆＃34;声明与＆＃34; if＆＃34;在同一行。示例如下。

function compare () {
if [ "$userChoice" == "$computerChoice" ] ; then
  echo "Empate!"
elif [ "$userChoice" == "piedra" ] ; then
  if [ "$computerChoice" == "tijeras" ] ; then
     echo "La piedra gana"
  else
     echo "El papel gana"
  fi
elif [ "$userChoice" == "papel" ] ; then
  if [ "$computerChoice" == "piedra" ] ; then
     echo "El papel gana"
  else
      echo "Las tijeras ganan"
  fi
fi
}
compare $userChoice $computerChoice

运行非常简单的shell脚本时出现语法错误

2 个答案: