Question

这是我展示ListPopupWindow

的代码

listPopupWindow = new ListPopupWindow(this); 
        listPopupWindow.setAnchorView(this.findViewById(android.R.id.content)); 

        final String[]messages = new String[MsgFromApp.getMessages().length];

        final ListAdapter adapter = new ArrayAdapter<String>(this, android.R.layout.simple_dropdown_item_1line, messages); 
        final AdapterView.OnItemClickListener itemClickListener = new AdapterView.OnItemClickListener() { 
            @Override 
            public void onItemClick(AdapterView<?> adapterView, View view, int position, long id) { 
                listPopupWindow.dismiss(); 
                listPopupWindow = null;
            } 
        };
        listPopupWindow.setModal(true);     listPopupWindow.setListSelector(getResources().getDrawable(R.drawable.message)); 
        listPopupWindow.setAdapter(adapter); 
        listPopupWindow.setOnItemClickListener(itemClickListener); 
        listPopupWindow.show();

它提供以下例外：引起：android.view.WindowManager $ BadTokenException：无法添加窗口 - 令牌null无效;你的活动在运行吗？

这有什么问题？＆安培;如何解决这个问题？

Answer 1

当应用程序尝试通过打开对话框从后台线程（AsyncTask）通知用户时，会发生此异常。请检查此链接：https://stackoverflow.com/a/18665887/4848308

Android中的ListPopupWindow中的异常

1 个答案: