Question

我想在这里做两件事。

如果输入不是此代码中的数字，我想打印"value entered is not a valid age"：

age = float(input (' enter your age:  '))
if 0 <age < 16:
    print "too early for you to drive"
if  120 >= age >= 95:
    print 'Sorry; you cant risk driving'
if age <= 0:
    print 'Sorry,' ,age, 'is not a valid age'
if age > 120: 
    print 'There is no way you are this old. If so, what is your secret?'
if 95 > age >= 16:
    print 'You are good to drive!'

此外，如果完成此程序，我该如何重复？

Answer 1

您可以使用isdigit str方法检查输入是否为有效数字。您可以多次将代码包装到函数中并根据需要调用它：

def func():
    age = input (' enter your age:  ')

    if age.isdigit():
        age = float(age)

        if 0 <age < 16:
            print "too early for you to drive"
        if  120 >= age >= 95:
            print 'Sorry; you cant risk driving'
        if age <= 0:
            print 'Sorry,' ,age, 'is not a valid age'
        if age > 120: 
            print 'There is no way you are this old. If so, what is your secret?'
        if 95 > age >= 16:
            print 'You are good to drive!'
    else:
        print "value entered is not a valid age"

func()

Answer 2

为了使这段代码在每次你应该添加一个循环时运行，比如while循环，并在你想要结束这个循环时添加一个break或添加一个条件例如运行10次，如果您想要检查输入是float，您可以添加try部分：

counter = 0
while counter < 10:
    age = raw_input (' enter your age:  ')
    try :
        age = float(age)
        if 0 <age < 16:
            print "too early for you to drive"
        if  120 >= age >= 95:
            print 'Sorry; you cant risk driving'
        if age <= 0:
            print 'Sorry,' ,age, 'is not a valid age'
        if age > 120: 
            print 'There is no way you are this old. If so, what is your secret?'
        if 95 > age >= 16:
            print 'You are good to drive!'
        counter -= 1
    except ValueError:
         print "value entered is not a valid age"

Answer 3

按顺序安排您的案例也是一个好主意，以便更容易看到正在发生的事情（并确保您没有留下未处理的差距）：

while True:
    age = input("Enter your age (or just hit Enter to quit): ").strip()

    if not age:
        print("Goodbye!")
        break       # exit the while loop

    try:
        # convert to int
        age = int(age)
    except ValueError:
        # not an int!
        print("Value entered is not a valid age")
        continue    # start the while loop again

    if age < 0:
        print("Sorry, {} is not a valid age.".format(age))
    elif age < 16:
        print("You are too young to drive!")
    elif age < 95:
        print("You are good to drive!")
    elif age <= 120:
        print("Sorry, you can't risk driving!")
    else:
        print("What are you, a tree?")

如果输入的值不是整数，如何打印输出

3 个答案: