Question

这适用于游戏mod文件共享网站。我有Apps Mods和游戏。每次抓住，你猜对了，Mods和游戏！

这是我的Mods模型：

from django.db import models
# Register storage backend TODO
def mod_directory_path(instance, filename):
    # file will be uploaded to MEDIA_ROOT/<game>/<filename>
    # Example code from https://docs.djangoproject.com/en/1.9/ref/models/fields/
    return 'user_{0}/{1}'.format(instance.user.id, filename)

# Create your models here.
class Mods(models.Model):
    title = models.CharField(max_length=30)
    author = models.CharField(max_length=30)
    game = models.ForeignKey(
        'games.Games',
        on_delete=models.CASCADE,
    )
    website = models.URLField()
    repoWebsite = models.URLField()
    upload = models.FileField(upload_to=mod_directory_path)

这是我的游戏模型：

from django.db import models

# Create your models here.
class Games(models.Model):
    title = models.CharField(max_length=30)
    developer = models.CharField(max_length=30)
    website = models.URLField()
    slug = models.SlugField()

我想将mod_directory_path自动设置为游戏模型的slu ..

例如，如果Mod项目“Dynamic War Sandbox”具有指向Arma 3游戏的唯一ID的ForeignKey，我希望文件上载路径基于Arma 3的数据库条目的slug。

MEDIA_ROOT/arma-3/<filename>.

我该怎么做？

Answer 1

这样的事情应该有效。唯一的要求是在创建mod之前游戏中已存在游戏。

def mod_directory_path(instance, filename):
    slug = instance.game.slug
    return os.sep.join([slug, filename])

Django FileField根据ForeignKey记录的slug字段生成路径

1 个答案: