我不知道这是否正确但由于某种原因我的存储过程在发生异常后没有回滚。所以即使我得到异常
,我的insert语句也会被提交我忘记了什么吗?
PROCEDURE SP_USUARIO_INSERT
(
pUSU_IDUSUARIO IN OUT ENG.USU_USUARIO.USU_IDUSUARIO%TYPE,
pUSU_CDUSUARIO IN ENG.USU_USUARIO.USU_CDUSUARIO%TYPE,
pPES_IDPESSOA IN ENG.USU_USUARIO.PES_IDPESSOA%TYPE,
pUSU_DLSENHA IN ENG.USU_USUARIO.USU_CDUSUARIO%TYPE,
pUSU_DLOBSERVACAO IN ENG.USU_USUARIO.USU_DLOBSERVACAO%TYPE,
pUSU_NUIP IN ENG.USU_USUARIO.USU_NUIP%TYPE,
pUSU_DTCADASTRO IN ENG.USU_USUARIO.USU_DTCADASTRO%TYPE,
pUSU_DTDESATIVACAO IN ENG.USU_USUARIO.USU_DTDESATIVACAO%TYPE,
pUSU_DTULTIMOACESSO IN ENG.USU_USUARIO.USU_DTULTIMOACESSO%TYPE,
pUSU_DLMAQUINA IN ENG.USU_USUARIO.USU_DLMAQUINA%TYPE,
pUSU_STNOVO IN ENG.USU_USUARIO.USU_STNOVO%TYPE,
pUSU_STATIVO IN ENG.USU_USUARIO.USU_STATIVO%TYPE
)
IS
sCreateUser Varchar(200);
bUsuarioExiste Number;
eUsuarioExiste Exception;
BEGIN
SELECT
COUNT(usu_cdusuario)
INTO bUsuarioExiste
FROM ENG.USU_USUARIO
WHERE USU_CDUSUARIO = pUSU_CDUSUARIO;
IF(bUsuarioExiste > 0) THEN
RAISE eUsuarioExiste;
END IF;
SELECT usu_seq.nextval INTO pUSU_IDUSUARIO FROM DUAL;
INSERT INTO ENG.USU_USUARIO
(
USU_IDUSUARIO,
USU_CDUSUARIO,
PES_IDPESSOA,
USU_DLOBSERVACAO,
USU_NUIP,
USU_DTCADASTRO,
USU_DTDESATIVACAO,
USU_DTULTIMOACESSO,
USU_DLMAQUINA,
USU_STNOVO,
USU_STATIVO
)
VALUES
(
pUSU_IDUSUARIO,
pUSU_CDUSUARIO,
pPES_IDPESSOA,
pUSU_DLOBSERVACAO,
pUSU_NUIP,
sysdate,
pUSU_DTDESATIVACAO,
pUSU_DTULTIMOACESSO,
pUSU_DLMAQUINA,
pUSU_STNOVO,
pUSU_STATIVO
) ;
sCreateUser := 'CREATE USER ' || pUSU_CDUSUARIO || ' IDENTIFIED BY ' || pUSU_DLSENHA;
EXECUTE IMMEDIATE sCreateUser;
EXECUTE IMMEDIATE 'GRANT ENG_GERAL TO ' || pUSU_CDUSUARIO;
COMMIT;
EXCEPTION
WHEN eUsuarioExiste THEN
RAISE_APPLICATION_ERROR (-20001, 'Usuário já existe ou possui nome inválido.');
ROLLBACK;
WHEN OTHERS THEN
RAISE_APPLICATION_ERROR (-20001, SQLCODE || ': ' || SQLERRM);
ROLLBACK;
END SP_USUARIO_INSERT;
答案 0 :(得分:5)
“EXECUTE IMMEDIATE sCreateUser;”隐含地提交你的插入。
答案 1 :(得分:1)
我怀疑你正在“处理”(或更准确地说,忽略)你的例外。
create table temp (id number);
DECLARE
v_str VARCHAR2(2);
BEGIN
INSERT INTO temp VALUES (1);
v_str := '123';
EXCEPTION
WHEN VALUE_ERROR THEN DBMS_OUTPUT.PUT_LINE('Whoops');
END;
/
select * from temp;
将显示该行,因为就SQL层而言,该过程已成功完成(因为异常被捕获并被忽略)。
可能还有其他原因,例如
答案 2 :(得分:0)
我认为如果您重构代码,就可以获得所需的行为。
PROCEDURE SP_USUARIO_INSERT
(
pUSU_IDUSUARIO IN OUT ENG.USU_USUARIO.USU_IDUSUARIO%TYPE,
pUSU_CDUSUARIO IN ENG.USU_USUARIO.USU_CDUSUARIO%TYPE,
pPES_IDPESSOA IN ENG.USU_USUARIO.PES_IDPESSOA%TYPE,
pUSU_DLSENHA IN ENG.USU_USUARIO.USU_CDUSUARIO%TYPE,
pUSU_DLOBSERVACAO IN ENG.USU_USUARIO.USU_DLOBSERVACAO%TYPE,
pUSU_NUIP IN ENG.USU_USUARIO.USU_NUIP%TYPE,
pUSU_DTCADASTRO IN ENG.USU_USUARIO.USU_DTCADASTRO%TYPE,
pUSU_DTDESATIVACAO IN ENG.USU_USUARIO.USU_DTDESATIVACAO%TYPE,
pUSU_DTULTIMOACESSO IN ENG.USU_USUARIO.USU_DTULTIMOACESSO%TYPE,
pUSU_DLMAQUINA IN ENG.USU_USUARIO.USU_DLMAQUINA%TYPE,
pUSU_STNOVO IN ENG.USU_USUARIO.USU_STNOVO%TYPE,
pUSU_STATIVO IN ENG.USU_USUARIO.USU_STATIVO%TYPE
)
IS
sCreateUser Varchar(200);
bUsuarioExiste Number;
eUsuarioExiste Exception;
l_sqlcode number;
BEGIN
SELECT
COUNT(usu_cdusuario)
INTO bUsuarioExiste
FROM ENG.USU_USUARIO
WHERE USU_CDUSUARIO = pUSU_CDUSUARIO;
IF(bUsuarioExiste > 0) THEN
RAISE eUsuarioExiste;
END IF;
sCreateUser := 'CREATE USER ' || pUSU_CDUSUARIO || ' IDENTIFIED BY ' ||
pUSU_DLSENHA;
EXECUTE IMMEDIATE sCreateUser;
begin
EXECUTE IMMEDIATE 'GRANT ENG_GERAL TO ' || pUSU_CDUSUARIO;
-- moved this into the insert
--SELECT usu_seq.nextval INTO pUSU_IDUSUARIO FROM DUAL;
INSERT INTO ENG.USU_USUARIO
(
USU_IDUSUARIO,
USU_CDUSUARIO,
PES_IDPESSOA,
USU_DLOBSERVACAO,
USU_NUIP,
USU_DTCADASTRO,
USU_DTDESATIVACAO,
USU_DTULTIMOACESSO,
USU_DLMAQUINA,
USU_STNOVO,
USU_STATIVO
)
VALUES
(
usu_seq.nextval, --pUSU_IDUSUARIO,
pUSU_CDUSUARIO,
pPES_IDPESSOA,
pUSU_DLOBSERVACAO,
pUSU_NUIP,
sysdate,
pUSU_DTDESATIVACAO,
pUSU_DTULTIMOACESSO,
pUSU_DLMAQUINA,
pUSU_STNOVO,
pUSU_STATIVO
)
returning ;
exception
when others then
-- save off the sqlcode, you will need it to reraise
l_sqlcode := SQLCODE;
-- rollback any insert that may have run,
-- depending on where the exception was raised
rollback;
-- drop the created user
execute immediate 'drop user ' || pUSU_CDUSUARIO ;
-- reraise the error
RAISE_APPLICATION_ERROR (-20001, l_sqlcode || ': ' ||
SQLERRM(-l_sqlcode));
end;
COMMIT;
EXCEPTION
WHEN eUsuarioExiste THEN
RAISE_APPLICATION_ERROR (-20001,
'Usuário já existe ou possui nome inválido.');
ROLLBACK;
WHEN OTHERS THEN
RAISE_APPLICATION_ERROR (-20001,
SQLCODE || ': ' || SQLERRM);
ROLLBACK;
END SP_USUARIO_INSERT;
答案 3 :(得分:0)
RAISE_APPLICATION_ERROR
是否意味着ROLLBACK
无法访问?除非调用者也发出ROLLBACK
,否则我认为那些需要反过来。你可能正在接受DDL的隐式提交,正如其他人所说,取决于实际上是错误的,所以它可能是无关紧要的,但它看起来不太正确。