Spring MVC Restful 406不可接受的错误

时间：2016-01-20 14:37:54

标签： spring rest spring-mvc curl

我知道之前已经问过这个问题了，我已经用406错误消息检查了Spring MVC的每条消息，我不知道如何解决这个问题，因为我已经尝试了所有放在第四位的东西以前的答案。

这一个Web服务接受一个电子邮件地址，并以JSON方式返回一个用户对象。我可以告诉你单元测试工作得很好。我知道我们通过Spring Security，我们正在执行servlet ...现在唯一的问题是JSON输出......我没有得到它，我收到此错误消息。

所以，确切地说：
Spring Core：4.2.4.RELEASE Spring Security：4.0.3.RELEASE Jackson Faster XML：2.6.5（核心，数据绑定，注释）                     2.7.0似乎还没有工作......

这是springmvc-servlet.xml：

<context:annotation-config />
<context:component-scan base-package="com.agmednet.server.controller" />

<mvc:annotation-driven>
    <mvc:message-converters register-defaults="true">
        <bean class="org.springframework.http.converter.json.MappingJackson2HttpMessageConverter">
          <property name="objectMapper">
             <bean class="com.agmednet.server.HibernateAwareObjectMapper">

                     <property name="dateFormat">
                        <bean class="java.text.SimpleDateFormat">
                            <constructor-arg type="java.lang.String" value="yyyy-MM-dd HH:mm:ss.SSS"></constructor-arg>
                        </bean>
                     </property>

             </bean>
          </property>
        </bean>
    </mvc:message-converters>
</mvc:annotation-driven>

这是控制器：

@Controller
@RequestMapping("/users")
public class UserAccountController
{
@Autowired
private UserAccountService userAccountService;

@RequestMapping(value = "/email/{email:.*}", method = RequestMethod.GET)
public @ResponseBody UserAccountEntity getByEmailAddress(@PathVariable("email") String email)
{
    Object principal = SecurityContextHolder.getContext().getAuthentication().getPrincipal();
    User user = null;
    if (principal instanceof User)
    {
        user = ((User) principal)
    }
    UserAccountEntity userAccount = userAccountService.getByEmailAddress(email);
    return userAccount;
}
}

如您所见，我有Accept标头设置，我有@ResponseBody注释。

我有一个SimpleCORSFilter代码：

@Component
public class SimpleCORSFilter implements Filter
{
    public void doFilter(ServletRequest req, ServletResponse res, FilterChain chain) throws IOException, ServletException
    {
    HttpServletResponse response = (HttpServletResponse) res;
    response.setHeader("Access-Control-Allow-Origin", "*");
    response.setHeader("Access-Control-Allow-Methods", "POST, PUT, GET, OPTIONS, DELETE");
    response.setHeader("Access-Control-Max-Age", "3600");
    response.setHeader("Access-Control-Allow-Headers", "x-requested-with, Content-Type, Accept, If-Modified-Since, openam_token");
    chain.doFilter(req, res);
    }

    public void init(FilterConfig filterConfig){}
    public void destroy(){}
}

正如您所看到的，这接受了我的自定义标头“openam_token”，但是有 “接受”和“内容类型”。

我从防火墙后面的一个linux框中调用它，所以我必须SSH进入机器，然后执行这个curl语句：

curl -v -i -X GET -H "openam_token: AQIC5wM2LY4Sfcxfw-GSBSndg-4DMEyrEqcBgiTE4b4e3aE.*AAJTSQACMDE.*" -H "Content-Type: application/json, text/html" -H "Accept: application/json, text/html" backend.spring.mycompany.net:8080/services/api/users/email/user4252002@mycompany.com

所以，这是我在请求中通过curl发送的内容：

*   Trying 10.0.4.107...
* Connected to backend.spring.agmednet.net (10.0.4.107) port 8080 (#0)
> GET /services/api/users/email/user4252002@agmednet.com HTTP/1.1
> User-Agent: curl/7.40.0
> Host: backend.spring.agmednet.net:8080
> openam_token: AQIC5wM2LY4Sfcxfw-GSBSndg-4DMEyrEqcBgiTE4b4e3aE.*AAJTSQACMDE.*
> Content-Type: application/json, text/html
> Accept: application/json, text/html

以下是回复：

< HTTP/1.1 406 Not Acceptable
HTTP/1.1 406 Not Acceptable
< Server: Apache-Coyote/1.1
Server: Apache-Coyote/1.1
< Access-Control-Allow-Origin: *
Access-Control-Allow-Origin: *
< Access-Control-Allow-Methods: POST, PUT, GET, OPTIONS, DELETE
Access-Control-Allow-Methods: POST, PUT, GET, OPTIONS, DELETE
< Access-Control-Max-Age: 3600
Access-Control-Max-Age: 3600
< Access-Control-Allow-Headers: x-requested-with, Content-Type, Accept, If-Modified-Since, openam_token
Access-Control-Allow-Headers: x-requested-with, Content-Type, Accept, If-Modified-Since, openam_token
< Cache-Control: no-cache, no-store, max-age=0, must-revalidate
Cache-Control: no-cache, no-store, max-age=0, must-revalidate
< Pragma: no-cache
Pragma: no-cache
< Expires: 0
Expires: 0
< X-XSS-Protection: 1; mode=block
X-XSS-Protection: 1; mode=block
< X-Frame-Options: DENY
X-Frame-Options: DENY
< X-Content-Type-Options: nosniff
X-Content-Type-Options: nosniff
< Set-Cookie: JSESSIONID=76C4B28DD0B5D88EB9341944BDBCD045; Path=/services/; HttpOnly
Set-Cookie: JSESSIONID=76C4B28DD0B5D88EB9341944BDBCD045; Path=/services/; HttpOnly
< Content-Type: text/html;charset=utf-8
Content-Type: text/html;charset=utf-8
< Content-Language: en
Content-Language: en
< Content-Length: 1110
Content-Length: 1110
< Date: Wed, 20 Jan 2016 14:30:28 GMT
Date: Wed, 20 Jan 2016 14:30:28 GMT


  <!DOCTYPE html>
  <html><head>
  <title>Apache Tomcat/8.0.30 - Error report</title>
  </head>
  <body>
  <h1>HTTP Status 406 - </h1>
  <div class="line"></div><p><b>type</b> Status report</p>
  <p><b>message</b> <u></u></p>
  <p><b>description</b> 
  <u>The resource identified by this request is only capable of generating 
  responses with characteristics not acceptable according to the request*  
  Connection #0 to host backend.spring.agmednet.net left intact
  "accept" headers.</u></p>
  <hr class="line"><h3>Apache Tomcat/8.0.30</h3></body></html>

最终，这是上面列出的错误消息：

The resource identified by this request is only capable of generating responses with characteristics not acceptable according to the request* Connection #0 to host backend.spring.mycompany.net left intact

“接受”标题。

所以，我正在使用@ResponseBody，我正在使用最新的Jackson 2.x版本。我正在遵循先前问题的所有建议，但仍然无法使其发挥作用。

非常感谢任何帮助。

1 个答案:

答案 0 :(得分：1)

@EnableWebMVC不是问题，你在问题中看到的一切都是100％正确的。我有两个其他网络服务工作正常。问题最终是卷曲声明本身：

curl -v -i -X GET -H /
"openam_token: AQIC5wM2LY4Sfcxfw-GSBSndg-4DMEyrEqcBgiTE4b4e3aE.*AAJTSQACMDE.*" /
-H "Content-Type: application/json, text/html" /
-H "Accept: application/json, text/html"  /
backend.spring.mycompany.net:8080/services/api/users/email/user4252002@mycompany.com

如果您注意到，URL和路径变量不在引号中。 如果你注意到，电子邮件地址中有一个@符号，我发现这意味着要卷曲。所以，我所做的就是将我的卷曲改为以下内容。

curl -v -i -X GET -H /
"openam_token: AQIC5wM2LY4Sfcxfw-GSBSndg-4DMEyrEqcBgiTE4b4e3aE.*AAJTSQACMDE.*" /
-H "Content-Type: */*" /
-H "Accept: */*" /    
"backend.spring.mycompany.net:8080/services/api/users/email/user4252002%40mycompany%2Ecom"

1）我将自己@的电子邮件地址编码为％40，将期间点编码为％2E 您可以使用任何工具来编码路径变量。

2）即使我返回一个转换为JSON的java对象，我也将标题“Accept”和“Content-Type”更改为“ / ”。

就是这样。这有效，406错误消息消失了。

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