Question

我想计算此数组中字符串中最后一个字符之前字符 t 的所有值（城市名称）。

ARRAY

$cities_array = array(
"city1" => "Paris_t1",
"city2" => "Madrid_t1",
"city3" => "Amsterdam_t1",
"city4" => "London_i1",
"city5" => "Miami_i1",
"city6" => "Berlin_i1",
"city7" => "Brussels_i1",
"city8" => "Toronto_i1",
);

结果应为： 3 （Paris_t1 - Madrid_t1 - Amsterdam_t1）

我相信我必须结合起来：

array_count_values($cities_array)

和

substr($value, -2, 1) == "t"

我试过，但我只得到错误。

Answer 1

这会给你你想要的东西。

        $cities_array = array(
                "city1" => "Paris_t1",
                "city2" => "Madrid_t1",
                "city3" => "Amsterdam_t1",
                "city4" => "London_i1",
                "city5" => "Miami_i1",
                "city6" => "Berlin_i1",
                "city7" => "Brussels_i1",
                "city8" => "Toronto_i1",
                );
$count = 0;
$city_text = '';
foreach($cities_array as $city){
    if(substr($city, -2, 1) == "t"){
        $count++;
        $city_text .= $city . '-';
    }
}

echo $count. "(".rtrim($city_text,'-').")";

Answer 2

尝试以下解决方案：

$cities_array = array(
    "city1" => "Paris_t1",
    "city2" => "Madrid_t1",
    "city3" => "Amsterdam_t1",
    "city4" => "London_i1",
    "city5" => "Miami_i1",
    "city6" => "Berlin_i1",
    "city7" => "Brussels_i1",
    "city8" => "Toronto_i1",
);

$filtered_array = array_filter($cities_array, function($val){
    return (strpos($val, 't', (strlen($val)-2)) !== false);
});

print_r($filtered_array);

输出 - （你可以通过以下方式内爆数组来获得所需的结果）

Array
(
    [city1] => Paris_t1
    [city2] => Madrid_t1
    [city3] => Amsterdam_t1
)

在strpos第三个参数strlen($val)-2)的上述解决方案中，即将从$val的第二个字符

搜索位置

计算具有特殊字符的数组中的vallues

2 个答案: