Question

我有一个xml abc.xml

<soapenv:Envelope>
   <soapenv:Header/>

   <soapenv:Body>
      <mes:SomeRq>

         <RqID>?</RqID>

         <MsgRqHdr>
         ....
      </mes:SomeRq>
   </soapenv:Body>
</soapenv:Envelope>

我有没有办法从这个xml中搜索mes:并将其替换为ins:

提前致谢。

public static void findreplcae(String strFilePath) throws IOException {
    String currentString = "mes:";
    String changedString = "ins:";
    BufferedReader reader = new BufferedReader(new FileReader(strFilePath));

    StringBuffer currentLine = new StringBuffer();
    String currentLineIn;
    while ((currentLineIn = reader.readLine()) != null) {
        System.out.println(currentLineIn);
        boolean bool = false;
        String trimmedLine = currentLineIn.trim();
        System.out.println(trimmedLine);
        if (trimmedLine.contains(currentString)) {
            trimmedLine.replace(currentString, changedString);
            bool = true;
            if (bool != true) {
                currentLine = currentLine.append(currentLineIn + System.getProperty("line.separator"));
            }
        }
        reader.close();
        BufferedWriter writer = new BufferedWriter(new FileWriter(strFilePath));
        writer.write(currentLine.toString());
        writer.close();
    }
}

Answer 1

将其解析为文本文件并不是一个好主意。 DocumentBuilder.parse要解析文件，请致电getDocumentElement()并检查getPrefix。如果匹配，请替换为setPrefix()。请注意，如果尚未注册，则必须注册前缀。

检查this page以获取教程。

Answer 2

一些问题：

bool = true; if (bool != true) { currentLine = currentLine.append(currentLineIn + System.getProperty("line.separator")); }，结果是返回，因此您必须将其存储在某处。请参阅here

这应该做什么？

String currentString = "mes:";
String changedString = "ins:";
try {
    BufferedReader reader = new BufferedReader(new FileReader(strFilePath));

    StringBuffer newContents = new StringBuffer();
    String currentLineIn = null;
    while ((currentLineIn = reader.readLine()) != null) {
        String trimmedLine = currentLineIn.trim();
        if (trimmedLine.contains(currentString)) {
            newContents.append(trimmedLine.replace(currentString, changedString));
        }
        else {
            newContents.append(trimmedLine);
        }
        newContents.append(System.getProperty("line.separator"));
    }

    reader.close();

    BufferedWriter writer = new BufferedWriter(new FileWriter(strFilePath));
    writer.write(newContents.toString());
    writer.close();

} catch (IOException e) {
    // TODO handle it
}

在循环阅读时不要关闭阅读器。

如果你想覆盖原始文件，这应该做（虽然我不确定，如果你真的想修剪线条）：

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如何从xml java中搜索和删除一些值

2 个答案: