Question

我正在处理Spring MVC中的csv文件（有大量记录）处理。如果文件有错误的记录，我需要写一个文件中有错误的所有记录，我还需要在网页上显示错误信息。

我的问题是，当我将记录写入文件时，应该如何显示错误消息。

以下是我的控制器代码无效

    @ResponseBody
    @RequestMapping(method = RequestMethod.POST, params = "bulkupload", produces = MediaType.APPLICATION_JSON_VALUE)
    public JsonResponse  handleFileUpload(@RequestParam(value = "file") MultipartFile csvFile, HttpServletResponse response) throws IOException{

        JsonResponse jsonResponse = new JsonResponse();
        try{
            RESULT result = bulkUploadService.processBulkData(csvFile.getInputStream());            

            if(result.code==RESULT.DATA_ERROR){
                jsonResponse.setResult( DATA_ERROR);
                response.setContentType("text/csv");
                response.setHeader("Content-disposition", "attachment;filename=errorList.csv");
                writeErrorToCSV(result.errorResult, new OutputStreamWriter(response.getOutputStream()));
            }else if (result.code == RESULT.SUCCESS){
                jsonResponse.setResult(SUCCESS);
            }
            jsonResponse.setStatus(JSON_RESPONSE_SUCCESS);
        }
        catch(Exception e){
            LOGGER.error(ExceptionUtils.getStackTrace(e));
            jsonResponse.setStatus(JSON_RESPONSE_ERROR);
            jsonResponse.setResult(UNKOWN_ERROR);
        }

        return jsonResponse;
}

客户端代码：

$("#bulkupload_form").submit(function(e){
e.preventDefault();
var mUrl= $(this).attr("action");
var oMyForm = new FormData();
oMyForm.append("file", $("#csvFile")[0].files[0]);
$.ajax({
    url : mUrl,
    type: "post",
    data: oMyForm,
    enctype: 'multipart/form-data',
    processData: false, 
    contentType:false,
    success : function(response) {
        if(response.status == "SUCCESS"){
            alert(response.result);
        }     
    } ,
    error: function() {

    }
});
});

spring mvc：如何下载文件并返回消息

0 个答案: