Question

我有以下型号

class Accept(models.Model):

    content_type = models.ForeignKey(ContentType)
    object_id = models.PositiveIntegerField(db_index=True)
    invitation = generic.GenericForeignKey('content_type', 'object_id')


class OfferBase(models.Model):

    user = models.ForeignKey(settings.AUTH_USER_MODEL)

    accepts = generic.GenericRelation(Accept)

    class Meta:
        abstract = True


class FooOffer(OfferBase):

    # pass


class BarOffer(OfferBase):

    # pass

我想计算按＃accept

排序的用户分组的＃次接受

在django，

FooOffer.object.values('user', 'user__username'
).annotate(num_accepts=Count('accepts__id')).order_by('-num_accepts')

在sql中，

SELECT "foo_offer"."user_id", "user"."username", COUNT("accept"."id") AS "num_accepts" FROM "foo_offer" INNER JOIN "user" ON ( "foo_offer"."user_id" = "user"."id" ) LEFT OUTER JOIN "accept" ON ( "foo_offer"."id" = "accept"."object_id" AND ("accept"."content_type_id" = 20\
2) ) GROUP BY "foo_offer"."user_id", "user"."username" ORDER BY "num_accepts" DESC


BarOffer.object.values('user', 'user__username'
).annotate(num_accepts=Count('accepts__id')).order_by('-num_accepts')

我想结合两个查询的结果（Foo和Bar）我不知道如何在sql中编写，我想我需要union和sum 我怎么在django那样做呢？也许用ORM可能无法做到这一点，那么如何在django世界中没有orm的情况下进行查询呢？

结果行将包含以下列。

user_id         username                sum( count(accept.id) )

django，通过查询组合两组

0 个答案: