您好我有here的以下代码段:
void handleGenieEvent(struct genieReplyStruct *reply) {
if (reply->cmd != GENIE_REPORT_EVENT) {
printf("Invalid event from the display: 0x%02X\r\n", reply->cmd) ;
return;
}
/**/
if (reply->object == GENIE_OBJ_KEYBOARD) {
if (reply->index == 0) // Only one keyboard
calculatorKey(reply->data);
else
printf("Unknown keyboard: %d\n", reply->index);
} else
if (reply->object == GENIE_OBJ_WINBUTTON) {
/**/
if (reply->index == 1) { // Clock button on main display
//do smth
} else
if (reply->index == 2) {
//do smth
} else
if (reply->index == 0) { // Calculator button on clock display
//do smth
} else
printf("Unknown button: %d\n", reply->index);
} else
printf("Unhandled Event: object: %2d, index: %d data: %d [%02X %02X %04X]\r\n",
reply->object, reply->index, reply->data, reply->object, reply->index, reply->data);
}
我想知道是否可以在此处使用切换,尤其是index
我试过了:
switch (reply->index)
case 0:
//do smth
case 1:
//do smth
case 2:
//do smth
但这不起作用。
答案 0 :(得分:3)
switch (reply->index)
{
case 0:
//do smth
break;
case 1:
//do smth
break;
case 2:
//do smth
break;
default:
printf("Unknown button: %d\n", reply->index);
break;
}
会奏效。
请注意,您的样本应在功能输入时检查reply
- 指针:
void handleGenieEvent (struct genieReplyStruct *reply)
{
if (NULL == reply)
{
// report error
return;
}
else
{
// ...
}
}
答案 1 :(得分:1)
在这种情况下,您应该使用括号和break语句:
switch (reply->index){ <---bracket
case 0:
//do smth
break;
case 1:
//do smth
break;
case 2:
//do smth
break;
}<---bracket
如果你想要与上面的if-else代码片段相同的功能,你需要break语句。例如,如果你错过了中断并得到了案例0,那么案例1和2也会执行。