Question

我是 iOS 9 和 Swift 2 的初学者。我有一个包含动态和分组内容的表格视图，我想将每个单元格与特定的视图控制器（不是详细控制器）链接。我知道如何使用带有segues的静态单元格来完成此操作，但我如何处理动态单元格呢？拳头，我使用动态单元格，因为我计划添加大量数据，其次是因为我实现了搜索控件以快速找到所需的条目。此外，当用户从搜索结果中选择单元格时，视图之间的此特定链接必须起作用。这是我的代码：

import UIKit

class TableViewController: UITableViewController, UISearchResultsUpdating {

// MARK: Properties

let section = ["Section 1", "Section"]
let names = [["Name 1", "Name 2", "Name 3"], ["Name 4", "Name 5", "Name 6", "Name 7", "Name 8"]]
var tableData = ["Name 1", "Name 2", "Name 3", "Name 4", "Name 5", "Name 6", "Name 7", "Name 8"] // Look for a way to convert directly from "names" array!
var filteredData:[String] = []
var resultSearchController:UISearchController!

override func viewDidLoad() {
    super.viewDidLoad()
    resultSearchController = UISearchController(searchResultsController: nil)
    resultSearchController.searchResultsUpdater = self
    resultSearchController.hidesNavigationBarDuringPresentation = false
    resultSearchController.dimsBackgroundDuringPresentation = false
    resultSearchController.searchBar.searchBarStyle = UISearchBarStyle.Prominent
    resultSearchController.searchBar.sizeToFit()
    self.tableView.contentOffset = CGPointMake(0,CGRectGetHeight(resultSearchController.searchBar.frame))
    self.tableView.tableHeaderView = resultSearchController.searchBar
}

override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
    // Dispose of any resources that can be recreated.
}

// MARK: - Table view data source

override func tableView(tableView: UITableView, titleForHeaderInSection section: Int) -> String? {
    if resultSearchController.active {
        return nil
    } else {
        return self.section[section]
    }
}

override func numberOfSectionsInTableView(tableView: UITableView) -> Int {
    // #warning Incomplete implementation, return the number of sections
    if resultSearchController.active {
        return 1
    } else {
        return self.section.count
    }
}

override func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
    // #warning Incomplete implementation, return the number of rows
    if resultSearchController.active {
        return filteredData.count
    } else {
        return self.names[section].count
    }
}

override func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
    let cell = tableView.dequeueReusableCellWithIdentifier("tableCell", forIndexPath: indexPath)

    // Configure the cell...
    if resultSearchController.active {
        cell.textLabel?.text = filteredData[indexPath.row]
    } else {
        cell.textLabel?.text = self.names[indexPath.section][indexPath.row]
    }
    return cell
}

func updateSearchResultsForSearchController(searchController: UISearchController) {
    if searchController.searchBar.text?.characters.count > 0 {
        filteredData.removeAll(keepCapacity: false)
        let searchPredicate = NSPredicate(format: "SELF CONTAINS %@", searchController.searchBar.text!)
        let array = (tableData as NSArray).filteredArrayUsingPredicate(searchPredicate)
        filteredData = array as! [String]
        tableView.reloadData()
    }
    else {
        filteredData.removeAll(keepCapacity: false)
        filteredData = tableData
        tableView.reloadData()
    }
}

我没有在任何地方找到解决方案。由于我没有多少经验，请写详细信息和一些代码。谢谢！

编辑：更具体：

func tableView(tableView: UITableView, didSelectRowAtIndexPath indexPath: NSIndexPath) {

// Here is the code I need to link the selected cell to the
// right View Controller in my storyboard. And this must work
// when the user pick the cell in search results view too.
// For example, if the cell contains "Name 1", it navigates
// to "View Controller 1".

}

Answer 1

您可以使用以下构造在触摸单元格时运行您自己的代码。

func tableView(tableView: UITableView, didSelectRowAtIndexPath indexPath: NSIndexPath) {
    // Your code here
}

您的代码可能是performSegue，或者您喜欢的任何其他内容。

Answer 2

感谢您的提示！这是我写的：

override func tableView(tableView: UITableView, didSelectRowAtIndexPath indexPath: NSIndexPath) {        let rowIndexPath = tableView.indexPathForSelectedRow!
    var nameString:String
    var segueString:String
    if resultSearchController.active {
        resultSearchController.active = false
        nameString = filteredData[rowIndexPath.row].lowercaseString
        segueString = "\(nameString)" + "View"
        self.performSegueWithIdentifier(segueString, sender: self)
    } else {
        nameString = self.names[rowIndexPath.section][rowIndexPath.row].lowercaseString
        segueString = "\(nameString)" + "View"
        self.performSegueWithIdentifier(segueString, sender: self)
    }
}

我创建了名为＆＃34; nameXView＆＃34;的segues。因此，例如，segue链接＆＃34;名称1＆＃34;和＆＃34;查看控制器1＆＃34;是＆＃34; name1View＆＃34;。然后，我可以根据细胞内容选择正确的segue。它也适用于搜索结果！

Answer 3

单击要链接的单元格，然后控制拖动到要显示的视图。然后选择您的选项Ex：Show，Present Modally等

如何将表格视图动态单元格链接到特定的视图控制器？

3 个答案: