首先发布在这里!
所以我有这段代码:
static boolean getInternationalCalls() {
Scanner intercalls = new Scanner(System.in);
System.out.println("Would the customer like International Calls to be included within their minutes?");
System.out.println("If yes, please enter Y, if no please enter N below.");
Scanner scanner = new Scanner(System.in);
if (scanner.next().equalsIgnoreCase("Y") || scanner.next().equalsIgnoreCase("yes")) {
System.out.println("Internatinal Calls will be included");
} else if (scanner.next().equalsIgnoreCase("N") || scanner.next().equalsIgnoreCase("no")) {
System.out.println("International Calls will not be included");
} else {
System.out.println("Invalid character, please enter Y or N");
}
困惑自己,不知道怎么写它的回复陈述
将其归还:
boolean interCalls = getInternationalCalls();
提前致谢! :)
答案 0 :(得分:0)
我希望这不是你的作业杰米。你的方法错过很多东西并且有语法错误。请使用像eclipse这样的IDE,这样会更容易。
static boolean getInternationalCalls() {
Scanner intercalls = new Scanner(System.in);
System.out.println("Would the customer like International Calls to be included within their minutes?");
System.out.println("If yes, please enter Y, if no please enter N below.");
Scanner scanner = new Scanner(System.in);
String input = null;
while (true) {
input = scanner.next();
if (input != null && (input.equalsIgnoreCase("Y") || input.equalsIgnoreCase("yes"))) {
System.out.println("Internatinal Calls will be included");
return true;
} else if (input != null && (input.equalsIgnoreCase("N") || input.equalsIgnoreCase("no"))) {
System.out.println("International Calls will not be included");
return false;
} else {
System.out.println("Invalid character, please enter Y or N");
}
}
}
答案 1 :(得分:0)
我得到了它:
static boolean getInternationalCalls(){ boolean internationalCalls = false; System.out.println(“客户是否愿意将国际电话纳入他们的会议记录?”); System.out.println(“如果是,请输入Y,如果没有,请在下面输入N.”);
Scanner scanner = new Scanner(System.in);
if (scanner.next().equalsIgnoreCase("y") || scanner.next().equalsIgnoreCase("yes")) {
System.out.println("Internatinal Calls will be included");
} else if (scanner.next().equalsIgnoreCase("n") || scanner.next().equalsIgnoreCase("no")) {
System.out.println("International Calls will not be included");
} else {
System.out.println("Invalid character, please enter Y");
}
return internationalCalls;
不,大声笑
侧面项目,结合到目前为止我所讲的所有内容