Question

我有一个MS Access查询（使用SQL创建），用于计算设备状态表中日期列中非NULL值的出现次数。该表包含特定制造工厂的所有设备。查询还计算总设备，我们没有NULL值。共有12种不同的植物，每种植物都有自己相同的Access表。我需要创建一个统一的SQL查询，将每个计数的总和创建为所有工厂的主计数。

状态表的结构名为“_review_status”：

equip_number, text
review_a_analysis, date
review_b_analysis, date 
review_c_analysis, date
review_d_analysis, date
review_e_analysis, date
review_f_analysis, date
review_g_analysis, date

工作查询的结果（在一个表上）看起来像这样。

a   b   c   d   e   f   g   equip_count
17  31  0   94  13  12  44  1249

新结果应该与上面的结果完全相同，只是数字会更大，因为查询会查看所有12组表。

以下是工作单表查询：

SELECT 
Count(dept1_review_status.review_a_analysis) AS a, 
Count(dept1_review_status.review_b_analysis) AS b, 
Count(dept1_review_status.review_c_analysis) AS c, 
Count(dept1_review_status.review_d_analysis) AS d, 
Count(dept1_review_status.review_e_analysis) AS e, 
Count(dept1_review_status.review_f_analysis) AS f, 
Count(dept1_review_status.review_g_analysis) AS g,
Count(dept1_equipment.dept1_equip_number) AS equip_count
FROM dept1_equipment 
LEFT JOIN dept1_review_status 
ON dept1_equipment.dept1_equip_number = 
dept1_review_status.dept1_equip_number;

dept1_equipment表上的连接用于获取每个部门中所有设备的完整计数。

非常感谢。

鲍勃

Answer 1

考虑通过聚合查询运行所有12个组的联合查询，然后使用保存的联合查询运行另一个最终聚合查询：

<强> UNION

SELECT 
   Count(dept1_review_status.review_a_analysis) AS a, 
   Count(dept1_review_status.review_b_analysis) AS b, 
   Count(dept1_review_status.review_c_analysis) AS c, 
   Count(dept1_review_status.review_d_analysis) AS d, 
   Count(dept1_review_status.review_e_analysis) AS e, 
   Count(dept1_review_status.review_f_analysis) AS f, 
   Count(dept1_review_status.review_g_analysis) AS g,
   Count(dept1_equipment.dept1_equip_number) AS equip_count
FROM dept1_equipment LEFT JOIN dept1_review_status 
ON dept1_equipment.dept1_equip_number = dept1_review_status.dept1_equip_number;

UNION ALL

SELECT 
   Count(dept2_review_status.review_a_analysis) AS a, 
   Count(dept2_review_status.review_b_analysis) AS b, 
   Count(dept2_review_status.review_c_analysis) AS c, 
   Count(dept2_review_status.review_d_analysis) AS d, 
   Count(dept2_review_status.review_e_analysis) AS e, 
   Count(dept2_review_status.review_f_analysis) AS f, 
   Count(dept2_review_status.review_g_analysis) AS g,
   Count(dept2_equipment.dept2_equip_number) AS equip_count
FROM dept2_equipment LEFT JOIN dept2_review_status 
ON dept2_equipment.dept2_equip_number = dept2_review_status.dept2_equip_number;

UNION ALL

SELECT 
   Count(dept3_review_status.review_a_analysis) AS a, 
   Count(dept3_review_status.review_b_analysis) AS b, 
   Count(dept3_review_status.review_c_analysis) AS c, 
   Count(dept3_review_status.review_d_analysis) AS d, 
   Count(dept3_review_status.review_e_analysis) AS e, 
   Count(dept3_review_status.review_f_analysis) AS f, 
   Count(dept3_review_status.review_g_analysis) AS g,
   Count(dept3_equipment.dept3_equip_number) AS equip_count
FROM dept3_equipment LEFT JOIN dept3_review_status 
ON dept3_equipment.dept3_equip_number = dept3_review_status.dept3_equip_number;

...other 9 tables...

<强> FINAL

SELECT Sum(unionqry.a), 
       Sum(unionqry.b), 
       Sum(unionqry.c), 
       Sum(unionqry.d), 
       Sum(unionqry.e), 
       Sum(unionqry.f), 
       Sum(unionqry.g), 
       Sum(unionqry.h), 
       Sum(unionqry.equip_count)
FROM unionqry

或者，如果MS Access允许，则可以将所有内容合并到一个查询中：

SELECT Sum(unionqry.a), 
       Sum(unionqry.b), 
       Sum(unionqry.c), 
       Sum(unionqry.d), 
       Sum(unionqry.e), 
       Sum(unionqry.f), 
       Sum(unionqry.g), 
       Sum(unionqry.h), 
       Sum(unionqry.equip_count)
FROM (...above union query)... As unionqry

跨多个Access表的SQL计数求和查询

1 个答案: