选项标记

Question

$sql1 = "SELECT c.comm FROM enquiry e JOIN comments c ON e.id = c.enquiryId where e.id = '$memberId' AND e.cmpId = '$companyId'";    
$result1 = mysqli_query($conn, $sql1);
echo "<select class='form-control' name='comment'>";
    while($row1 = mysqli_fetch_array($result1, MYSQLI_ASSOC)){
        echo "
  <option value='".$row1['comm']."'>".$row1['comm']."</option>

    </select>";
 }

我想在选项中回显c.comm的所有值，但在获取ptint时只有一个值 请帮忙

Answer 1

将结束</select>标记放在while循环之后。

Answer 2

尝试编写select标签，如下所示：

  <select class="form-control" name="comment">
    $sql1 = "SELECT c.comm FROM enquiry e JOIN comments c ON e.id =   c.enquiryId where e.id = '$memberId' AND e.cmpId = '$companyId'";    
    $result1 = mysqli_query($conn, $sql1);
   while($row1 = mysqli_fetch_array($result1, MYSQLI_ASSOC)){
     echo "<option value='".$row1['comm']."'>".$row1['comm']."</option>

  }
 </select>