为什么我不能使用TCP客户端发送两条消息? (续)

时间:2016-01-19 13:50:13

标签: c# python sockets tcp

这是an earlier question的延续。我正在开始一个新线程,以便我可以显示最新的完整服务器和客户端代码,包括我在该线程和Reddit上收到的所有建议。

我在Windows 7专业版下运行。

我有一个用Python编写的非常简单的TCP服务器。它创建一个socketserver对象并等待消息。当一个人到达时,服务器将其打印到其控制台并通过同一端口发送一个简单的确认。

客户端向服务器发送编号的消息,等待确认并显示它。然后它询问用户是否应该发送另一条消息。

第一条消息已成功发送和确认。在客户端,似乎第二条消息发送成功;对网络流的Write()方法的调用成功。但是,当调用Read()消息来获取确认时,会抛出异常:“已建立的连接已被主机中的软件中止。”

这是服务器代码:

import json
import threading

import socketserver
import time

with open('CAPS_TWMS_config.json', 'rt') as c:
    caps_config = json.load(c)

# We are listening on this port and all defined IP addresses
# listenPort = 5001
listenPort = caps_config["listen_port"]

# Were to send the information to.
clientIPAddress = '127.0.0.1'   # socket.gethostbyname('client')
# clientPort = 12345
clientPort = caps_config["send_port"]

dsnName = caps_config["dsn_name"]

# Message sequence number
sequence_num = 1
exit_app = False

class ListenSocketHandler(socketserver.BaseRequestHandler):
    """
    The RequestHandler class for our server.

    It is instantiated once per connection to the server, and must
    override the handle() method to implement communication to the
    client.
    """
    def __init__(self, request, client_address, this_server):
        socketserver.BaseRequestHandler.__init__(self, request, client_address, this_server)
        self.timeout = 10

    def handle(self):
        try:
            data = self.request.recv(1024).decode()
            # print (str.format("dataString[21]: {0}; dataString[24:26]: {1}", data[21], data[24:26]))
            print ('ListenSocketHandler recv()-> "%s"' % data)
            print ('ListenSocketHandler recv().length-> "%d"' % len(data))

            if len(data) > 0:
                self.request.send("I got a message!".encode())
                return
        except Exception as value:
            print('ListenSocketHandler - %s' % str(value))

        return


class ListenServer(socketserver.ThreadingMixIn, socketserver.TCPServer):
    """
    The multi-threaded server that will spawn threads running the Socket Handler for each
    connection
    """
    pass

if __name__ == '__main__':

    try:
        # Create the Server Handler for connections to this computer listening on all IP addresses,
        # change '' to 'x.x.x.x'  to listen on a specific IP network.  This class will listen for messages    # from CAPS.
        server = ListenServer(('', listenPort), ListenSocketHandler)
        ip, port = server.server_address

        # Start a thread with the server -- that thread will then start one
        # more thread for each request
        server_thread = threading.Thread(target=server.serve_forever)
        # Exit the server thread when the main thread terminates
        server_thread.setDaemon(True)
        server_thread.start()

        while not exit_app:
            time.sleep(1)

        print ('Out of main loop.')
        server.shutdown()
        server.server_close()
    except Exception as value:
        print("Failed to do something: %s", str(value))

以下是客户端代码:

private void button1_Click(object sender, EventArgs e)
{
    TcpClient client = new TcpClient();

    try
    {
        client.Connect("127.0.0.1", 5001);
        NetworkStream stream = client.GetStream();
        int messageCount = 1;

        while (true)
        {                    
            // Translate the passed message into ASCII and store it as a Byte array.
            string message = string.Format("This is message {0}", messageCount++);
            Byte[] data = System.Text.Encoding.ASCII.GetBytes(message);


            // Send the message to the connected TcpServer. 
            stream.Write(data, 0, data.Length);

            // Receive the TcpServer.response.

            // Buffer to store the response bytes.
            data = new Byte[1024];

            // String to store the response ASCII representation.
            String responseData = String.Empty;

            // Read the first batch of the TcpServer response bytes.
            Int32 receivedCount = 0;
            int sleepCount = 0;
            while (receivedCount == 0)
            {                        
                receivedCount = stream.Read(data, 0, data.Length);
                responseData = System.Text.Encoding.ASCII.GetString(data, 0, receivedCount);
                if (receivedCount == 0)
                {
                    Thread.Sleep(250);
                    if (sleepCount++ > 20)
                    {
                        MessageBox.Show("Response timeout.");
                        break;
                    }
                }
            }

            if (MessageBox.Show("Reply: " + responseData + "  Try again?", "Try again?", MessageBoxButtons.YesNo) == DialogResult.No)
            {
                break;
            }

        }
        client.Close();
    }
    catch (Exception ex)
    {
        MessageBox.Show("Failed to do something with TcpClient: " + ex.Message);
    }
}

1 个答案:

答案 0 :(得分:0)

在您的代码中,每次连接新客户端时,它都会读取数据并向客户确认并且处理程序在以下语句后立即关闭(即返回)

 self.request.send("I got a message!".encode())
                return

因此连接已关闭。来自客户端的进一步命令未发送。您可以在循环中等待接收和确认。