Question

我需要能够在casper.then内设置一个特定的网址，以便在稍后的casper.thenOpen中打开。这是我设置的示例代码示例代码：在casper.then函数内部，我将打开一个页面并找到要打开的URL。我该如何修复我的代码？提前谢谢！

var casper = require('casper').create();

casper.base_uri = "https://www.google.it";

casper.start(casper.base_uri, function(){

    this.echo('Base URL: ' + this.getCurrentUrl());

});

casper.then(function(){

    // Here I will set the code to find the url to use: by now I am placing a fake one
    casper.base_uri = "https://www.google.fr"

});

casper.thenOpen(casper.base_uri, function () {

    this.echo('Changing URL to ' + casper.base_uri);
    this.echo('Current URL: ' + this.getCurrentUrl());

});

casper.run();

结果如下：

Base URL: https://www.google.it/
Changing URL to https://www.google.fr
Current URL: https://www.google.it/

请帮忙！保罗

CasperJS，无法从变量打开URL

0 个答案: