Question

我有一个像这样的数组

  Array
 (
[solar] => Array
    (
        [0] => sun
        [1] => moon
    )

[SolarGraph] => Array
    (
        [0] => Array
            (
                [y] => 89
                [url] => sun
            )

        [1] => Array
            (
                [y] => 57
                [url] => moon
            )

    )

  )

但我需要更改y和url名称，如下所示：

 Array
 (
[solar] => Array
    (
        [0] => sun
        [1] => moon
    )

[SolarGraph] => Array
    (
        [0] => Array
            (
                [solarvalue] => 89
                [solarname] => sun
            )

        [1] => Array
            (
                [solarvalue] => 57
                [solarname] => moon
            )

    )

  )

我试图改变，但我只得到一个数组......继承人代码

      foreach($Rows as $key=>$val){

        $aUse[] = $val['rt_solargraph'];

        foreach($aUse as $key => $value)
         {
          $aUser['SolarGraph'][$key]['SolarValue'] = $value[$key]['y'];
          $aUser['SolarGraph'][$key]['SolarName'] = $value[$key]['url'];

         }

      }

请帮帮我修复此问题，因为我是php和array的新手。我不知道如何迭代内部数组中的元素。

Answer 1

您可以这样使用：

<?php
use Symfony\Component\HttpFoundation\Request;
$login = $app['controllers_factory'];

$login->post('/apiv1/user/login', function (Request $request) use ($login) {
//                                                                ^^^^^^^^
// this should be $app, not $login as this function is using the container
    $userinfo = array(
        'email'  => $request->request->get('email'),
        'mode'  => $request->request->get('mode'),
        'password'  => $request->request->get('password'),
    );
    $passwordcoding = sha1($userinfo['email']."66643asd");
    $emailverification = "SELECT email,password FROM user WHERE email='".$userinfo['email']."'";

    // here you're using the $login as the container and it's a controller collection, so in the signature use the container not the $login
    //             vvvvvvvvvvvv
    $selectemail = $login['db']->$fetchAll('SELECT * FROM user');

    var_dump($emailverification);
});
return $login;

<强>结果：

// initialize array
$newArr = array();
foreach ($yourArr as $key => $value) {
    // if $value is array , you can also add SolarGraph key check.
    if(is_array($value) && $key == 'SolarGraph'){
        foreach ($value as $mykey => $finalVal) {
            // assign values to $newArr
            $newArr[$key][$mykey]['solarvalue'] = $finalVal['y'];
            $newArr[$key][$mykey]['solarname'] = $finalVal['url'];
        }
    }
    else{
        // if not is array store as same
        $newArr[$key] = $value;
    }
}

echo "<pre>";
print_r($newArr);

Answer 2

试试这个。

<?php 
    $solar = array('sun','moon');

    $SolarGraph  = array(array('y' => 89,'url'=>'sun' ),array('y' => 57,'url'=>'moon' ));

    $Rows  = array('solar'=>$solar, 'SolarGraph'=>$SolarGraph );
    echo '<pre>';

    $newArray = [];
    foreach ($Rows as $key => $value) {


        if($key =='SolarGraph'){

            foreach ($value as $lkey => $finalvalue) {
                 $newArray[$key][$lkey]['solarvalue'] = $finalvalue['y'];
                 $newArray[$key][$lkey]['solarname'] = $finalvalue['url'];  
            }
        }else{
            $newArray[$key] = $value;
        }

    }

     print_r($newArray);

    echo '</pre>';
?>

阵列中的Foreach数组Php

2 个答案: