Question

我使用Jackson XmlMapper读取XML字符串并将其转换为JsonString。我的XML文件是：

<root>
<catalog>
   <book id="bk101">
      <author>Gambardella, Matthew</author>
      <title>XML Developer's Guide</title>
      <genre>Computer</genre>
      <price>44.95</price>
      <publish_date>2000-10-01</publish_date>
      <description>An in-depth look at creating applications 
      with XML.</description>
   </book>
   <book id="bk105">
      <author>Gambardella, Matthew</author>
      <title>XML Developer's Guide</title>
      <genre>Computer</genre>
      <price>44.95</price>
      <publish_date>2000-10-01</publish_date>
      <description>An in-depth look at creating applications 
      with XML.</description>
   </book>
   <book id="bk114">
      <author>Gambardella, Matthew</author>
      <title>XML Developer's Guide</title>
      <genre>Computer</genre>
      <price>44.95</price>
      <publish_date>2000-10-01</publish_date>
      <description>An in-depth look at creating applications 
      with XML.</description>
   </book>
</catalog>
</root>

我为转换编写的代码是：

XmlMapper xmlMapper = new XmlMapper();
List entries = xmlMapper.readValue(file, List.class);
ObjectMapper jsonMapper = new ObjectMapper();
String json = jsonMapper.writeValueAsString(entries);

我得到的Json字符串是：

{
  "id": "569df9c1e4b0e505eb9fb913",
  "json": [
    {
      "book": {
        "id": "bk114",
        "author": "Gambardella, Matthew",
        "title": "XML Developer's Guide",
        "genre": "Computer",
        "price": "44.95",
        "publish_date": "2000-10-01",
        "description": "An in-depth look at creating applications \n          with XML."
      }
    }
  ],
  "fileType": "xml"
}

只有最后一本书被映射到Json String。 Answer to a similar question建议将xml字符串读入其对象类而不是通用列表类。但我尝试处理的XML文件是通用的，并没有固定的POJO表示。我该如何处理这个问题？

谢谢！

Answer 1

解决了这个问题。使用org.json.XML toJsonObject函数将XML转换为JSON。此XML解析器能够解析复杂的XML文件，如问题中的那个。

Jackson XmlMapper XML到Json的转换问题

1 个答案: