我想从我的表格中选择图像以显示在产品预览滑块上,如Demo。
TABLE fm_product_image
| img_id | p_id_img | img_name |
-----------------------------------------
| 1 | 60 | upload/demo_2.jpg |
| 2 | 60 | upload/demo_3.jpg |
<?php
include('connect.php');
?>
<!doctype html>
<html lang="en" class="no-js">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1">
<link href='http://fonts.googleapis.com/css?family=PT+Sans:400,700' rel='stylesheet' type='text/css'>
<link rel="stylesheet" href="css/reset.css"> <!-- CSS reset -->
<link rel="stylesheet" href="css/style.css"> <!-- Resource style -->
<script src="js/modernizr.js"></script> <!-- Modernizr -->
<title>TEST</title>
</head>
<body>
<ul class="cd-gallery">
<li style="cursor: pointer;">
<ul class="cd-item-wrapper">
<?php $result= mysql_query("SELECT img_name FROM fm_product_image WHERE p_id_img = 60") or die (mysql_error());
while ($rows = mysql_fetch_array ($result) ){ ?>
<li class="selected">
<img src="<?php echo $rows['img_name']; ?>" alt="Preview image">
</li>
<?php } ?>
</ul> <!-- cd-item-wrapper -->
<div class="cd-item-info">
<b><a href="#0">TEST</a></b>
<em class="cd-price">$26</em>
</div> <!-- cd-item-info -->
</li>
</ul> <!-- cd-gallery -->
<script src="js/jquery-2.1.1.js"></script>
<script src="js/jquery.mobile.min.js"></script>
<script src="js/main.js"></script> <!-- Resource jQuery -->
</body>
</html>
我的代码通过显示两个图像给出输出,我无法点击移动幻灯片。
答案 0 :(得分:1)
将此代码放入滑块部分
<?php $result= mysql_query("SELECT img_name FROM fm_product_image WHERE p_id_img = 60") or die (mysql_error());
$i=1;
while ($rows = mysql_fetch_array ($result) ){ ?>
<li <?php if($i==1){?>class="selected"<?php }?>>
<img src="<?php echo $rows['img_name']; ?>" alt="Preview image">
</li>
<?php $i++;} ?>
希望这会对你有帮助!