Question

所以，我正在我的网站上创建一个简单的搜索页面，而我只想选择最相关的信息。

为了做到这一点，我想从2个不同的表中选择数据。但我只想选择与搜索查询匹配的数据。

现在，这是有趣的部分。我只想选择出现次数最多的$ variable数据，然后将数据从最高到最低排序，然后限制结果数量（达到1,000或2,000）

用较小的词/代码形式询问。我想在SQL中运行这样的东西（由PHP运行）

$query = ["search","me","please"];
$maxData = 1500;
foreach($query as $value){
   //SQL start(Part I need help on)
   $res1 = SELECT * from table1 WHERE column LIKE %$value% AND return columns with highest times $value appears LIMIT $maxData

   $res2 = SELECT * from table2 WHERE column1,column2,column3 LIKE %$value% AND return columns with highest times $value appears LIMIT $maxData

}

我想要计算搜索变量在列中出现的次数，并按照从最高计数到最低计数的顺序返回时间

单独使用SQL是否可以实现这一切？

另外，如果我的问题不清楚或难以理解，请说出来。

Answer 1

您可以使用mysql 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查看更多详情here

Answer 2

可以使用group by语句和使用帮助程序表使用sql来完成。

使用一列search_term创建表tbl_search作为varchar。

每次执行查询时，此表都将被截断并重新填充搜索词。

Select * from
(Select search_term, count(*) as hits 
from table1 , tbl_search 
where table1.column like '%' + tbl_search.search_term +'%'
Group by tbl_search.search_term) as z1
Order by hits

索引tbl_search.search_term以帮助查询性能。

表中的SQL计数值仅返回最高5

2 个答案: