Question

我有一个问题，我使用Sequelize来运行查询，然后在第一个语句中返回对象，然后在另一个表上运行查询。在运行该查询之后，我有一个额外的then语句，该语句应该传递返回的对象以便能够在我的视图中访问。不幸的是，第二个查询不返回对象，因为控制台日志返回undefined第二个日志（Check console.log(member)）。出现这种情况的原因或我做错了什么？查询带有正确的陈述。

appRoutes.route('/settings/add-users')

    .get(function(req, res){
        models.Organization.find({
            where: {
                organizationId: req.user.organizationId
            }, attributes: ['organizationId', 'organizationName','admin','members']
        }).then(function(organization, member){
            models.Member.findAll({
                where: {
                    organizationId: organization.organizationId
                }, attributes: ['memberEmail']
            });
            return organization;
        }).then(function(organization, member){

            console.log(organization);
            console.log(member);
            res.render('pages/app/add-users.hbs',{
                user: req.user,
                organization: organization,
                member: member
            });
        }).catch(function(error){
            res.send(error);
            console.log(error);
        })
    });

Answer 1

承诺只能解析为单个值。您将从当时再次返回organization，因此下一个then会将其作为其值。您可以使用对象来实现所需的行为。

appRoutes.route('/settings/add-users')

    .get(function(req, res){
        var organization;

        models.Organization.find({
            where: {
                organizationId: req.user.organizationId
            }, attributes: ['organizationId', 'organizationName','admin','members']
        }).then(function(_organization){
            organization = _organization;
            return models.Member.findAll({
                where: {
                    organizationId: organization.organizationId
                }, attributes: ['memberEmail']
            });
        }).then(function(member){

            console.log(organization);
            console.log(member);
            res.render('pages/app/add-users.hbs',{
                user: req.user,
                organization: organization,
                member: member
            });
        }).catch(function(error){
            res.send(error);
            console.log(error);
        })
    });

JavaScript承诺不返回对象

1 个答案: