Question

为什么这段代码没有运行警报（“out of loop”）？它位于功能块内部并且不在for循环中，因此在完成循环后，必须运行下一个警报（“循环”）的状态。所以当两个输入都为真时它为什么不运行（用户：Amir.Nassaji传递：aaaaaaaaaaaa）

<body >
<form onsubmit="return loginCheck()" action= "#" 
method="Post">
username:<input type= "text" name= "username" class= "login" /><span class= "validation"></span><br />
password:<input type= "password" name= "password"  class= "login"/><span class= "validation"></span><br />
<input type= "submit" value= "submit" />
</form>



<script>
"using strict";
function loginCheck() {
  var fault = "";
  var ides = ["username" , "password"];   
  var inputs = document.getElementsByClassName("login");
  var inputSpans = document.getElementsByClassName("validation");
  var i = 0;
  for(i; i<inputs.length ; i++) {

    var inputValue = inputs[i].value;
    try {
      inputSpans[i].innerHTML = "";
      if (inputs[i].value === "") {
        throw " fild " + ides[i] + " is required.";
      }
      if (inputs[i].value.length < 8) {
        throw ides[i] + " must have at least 8 char length.";
      }
      if (!inputs[i].value.search(/^\d/i) && i === 0) {
        throw  ides [i] + " this filed can't start with number";
      }
      if (inputs[i].value.search(/[~!@#$%^&*\/><":;',()+=-]/i) !== -1 && i === 0) {
        throw  ides [i] + " there is unaccepted chars in field. ";
      }

    } catch(err) {

      inputSpans[i].innerHTML = "*" + " " + err;
      fault = err;
    } finally {
      alert (i+": finally run " + fault); // this is for testing running finally
      if ( i === 1 && fault != null) {
        return false;
      } else {
        continue;
      }
    }

  }
  alert ("out of loop");

}

</script>
</body>

Answer 1

如果您只有一个输入，请参阅小提琴：https://jsfiddle.net/16q2xr8k/11/

触发提醒

如果您有两个输入，请参阅小提琴：https://jsfiddle.net/16q2xr8k/10/

未触发提醒

此条件是说如果多于一个输入返回false而最后一个alert()将不会被调用

if ( i === 1 && fault != null) {
    return false;
}

为什么这段代码没有运行警报（“out of loop”）

1 个答案: