如何将ASCII字符串转换为C中字符的十进制值？

Question

例如：

• “16”应打印出小数值：49,54
• “24”应打印出小数值：50,52

我如何实现这一目标？

Answer 1

这很简单，你不需要转换任何代表问题，例如

const char *sixteen = "16";
const char *twentyfour = "24";
const char *number = "1345461";

printf("%d,%d\n", sixteen[0], sixteen[1]);
printf("%d,%d\n", twentyfour[0], twentyfour[1]);
//       ^  ^ use the `%d' specifier to see the decimal value
//            of the corresponding ascii.
for (int i = 0 ; number[i] != '\0' ; ++i)
    printf("%d,", number[i]);