使用Power Query动态重命名一组列

时间:2016-01-18 15:47:44

标签: powerquery

我正在尝试动态重命名Power Query中的一组列,List1是原始列名,List2是新列名。我想我需要将List1和List2合并到一个对的列表中,但不能找出正确的语法。

非常感谢!

    let

    //list of original column names 
    List1= {"Name1","Name2","Name3","Name4"},

    //Create test table
    Source = Table.FromRows({{1231,1233,4121,5232},{3546,3426,1246,3464}} , List1),

    //list of new column names
    List2 = {"NewName 1","NewName 2","NewName 3","NewName 4"},

    //Rename columns (in practice, the two lists of names will be dynamic, not hard coded as below)
    Result = Table.RenameColumns(Source, {
        {"Name1","NewName 1"},
        {"Name2","NewName 2"},
        {"Name3","NewName 3"},
        {"Name4", "NewName 4"}})

    in
        Result

4 个答案:

答案 0 :(得分:3)

如果您有一个包含旧名称和新名称的表格,则可以使用以下模式

let
    rename_list = Table.ToColumns(Table.Transpose(Table2)),
    result = Table.RenameColumns(Table1, rename_list, MissingField.Ignore)
in result

其中Table2是"重命名表"和Table1是包含数据的初始表。

这个想法在这里详细描述 https://bondarenkoivan.wordpress.com/2015/04/17/dynamic-table-headers-in-power-query-sap-bydesign-odata/

答案 1 :(得分:1)

如果您有所需的结果列名称,似乎您可以将Source转换回行,然后在Table.FromRows上调用List2

let

    //list of original column names 
    List1= {"Name1","Name2","Name3","Name4"},

    //Create test table
    Source = Table.FromRows({{1231,1233,4121,5232},{3546,3426,1246,3464}} , List1),

    //list of new column names
    List2 = {"NewName 1","NewName 2","NewName 3","NewName 4"},

    Result = Table.FromRows(Table.ToRows(Source), List2)

in
    Result

(除非假设Name 2始终是第二列是错误的。)

答案 2 :(得分:0)

最后......使用以下功能

计算出来

Table.TransformColumnNames(表为表,nameGenerator为函数,可选选项为可空记录)为表

首先创建一个nameGenerator函数(例如MyFuncRenameColumns),在给定任何原始列名作为输入的情况下提供新的列名。

在我的示例中,这是MyFuncRenameColumns的代码:

active_links(

在这里,您将其用作Table.TransformColumnNames的参数之一:

    let
        MyFunctionSwitchColumnName = (originalColumnName) as text =>
        let
            //list of original column names 
            List1= {"Name1","Name2","Name3","Name4"},

            //Create table
            Source = Table.FromRows({{1231,1233,4121,5232},{3546,3426,1246,3464}} , List1),

            //list of new column names
            List2 = {"NewName 1","NewName 2","NewName 3","NewName 4"},

            //Create table matching List1 to corresponding new value in List2
            CreateRecord = Record.FromList(List2,List1),
            ConvertedtoTable = Record.ToTable(CreateRecord),

            //Filter table to just the row where the input originalColumnName matches 
            ReduceExcess = Table.SelectRows(ConvertedtoTable, each [Name] = originalColumnName),

            //Return the matching result in the [Value] column (or give the original column name if there was no valid match)
            NewColumnName = try ReduceExcess{0}[Value] otherwise originalColumnName

        in 
            NewColumnName
    in
        MyFunctionSwitchColumnName

希望能帮助别人!

答案 3 :(得分:0)

根据伊万的解决方案陈述原始问题,这里是。 Carl的结果相同,对于我给出的例子来说有点简单,但是,我的情况将受益于在表格中明确列出重命名对(即表2)。另外,将MissingField.Ignore参数与Table.RenameColumns一起使用意味着它只会更改我想在生产查询中重命名的列的选择,其余的将保持不变。

let

    //list of original column names 
    List1= {"Name1","Name2","Name3","Name4"},

    //Create test table
    Source = Table.FromRows({{1231,1233,4121,5232},{3546,3426,1246,3464}} , List1),

    //list of new column names
    List2 = {"NewName 1","NewName 2","NewName 3","NewName 4"},

    //Rename columns (in practice, the two lists of names will be dynamic, not hard coded as below)

    //Bring List1 and List2 together as rows in a table
    Table2 = Table.FromRows({List1,List2}),

    //Create a list of rename pairs 
    RenameList = Table.ToColumns(Table2),

    //Call to Table.RenameColumns 
    Result = Table.RenameColumns(Source, RenameList, MissingField.Ignore)

in
    Result