Question

我有几个类型参数的功能。如何告诉编译器这些类型实际上是类型类？

trait Sizeable[-T, +R] {
  def mySize(x: T): R
}

implicit object StringSize extends Sizeable[String, Int] {
  def mySize(s: String) = s.length
}

def sum[T, R: Sizeable[T, R]](xs: List[T]): R =  xs.map(x => x.mySize)

错误是：

Error:(9, 14) A$A40.this.Sizeable[T,R] does not take type parameters 
def sum[T, R: Sizeable[T, R]](xs: List[T]): R =  xs.map(x => x.mySize);}

Answer 1

在这种情况下，您无法使用上下文绑定。您必须明确地编写隐式参数：

def foo[T, R](xs: List[T])(implicit sizeable: Sizeable[T,R]): List[R] =
  xs.map(x => sizeable.mySize(x))

键入具有许多类型参数的类

1 个答案: