抱歉我的英文。我有一个方法,我将StorageFile发送到服务器。我尝试使用Windows.Web.Http.HttpClient
,但无效(从服务器获得无效响应),因此我使用System.Net.Http.HttpClient
。
这是我的代码:
public static async void Upload(string uri, StorageFile data, Action<double> progressCallback = null)
{
try
{
byte[] fileBytes =await ReadFile(data);
System.Net.Http.HttpClient client = new System.Net.Http.HttpClient();
MultipartContent content = new System.Net.Http.MultipartFormDataContent();
var file1 = new ByteArrayContent(fileBytes);
file1.Headers.ContentDisposition = new ContentDispositionHeaderValue("form-data")
{
Name = "file1",
FileName = data.Name,
};
content.Add(file1);
System.Net.Http.HttpResponseMessage response = await client.PostAsync(uri, content);
response.EnsureSuccessStatusCode();
var raw_response = await response.Content.ReadAsByteArrayAsync();
var r2 = Encoding.UTF8.GetString(raw_response, 0, raw_response.Length);
if (r2[0] == '\uFEFF')
{
r2 = r2.Substring(1);
}
Logger.Info(r2);
}
catch (Exception exc)
{
Logger.Error( exc);
}
}
是否可以更改代码以接收有关在回调函数中下载文件的进度?
答案 0 :(得分:0)
在Windows运行时,您可以尝试切换到Windows.Web.HttpClient
课程。其PostAsync
方法返回IAsyncOperationWithProgress<HttpResponseMessage, HttpProgress>
接口。此接口具有Progress
事件,您可以在等待结果之前简单地订阅该事件。
答案 1 :(得分:0)
上传文件的最简单方法
我遇到了同样的问题,经过多次尝试后发现,您可以通过跟踪要上传的文件的 FileStream 的 Position
轻松获得字节精确的进度。
这是说明这一点的示例代码。
FileStream fileToUpload = File.OpenRead(@"C:\test.mp3");
HttpContent content = new StreamContent(fileToUpload);
HttpRequestMessage msg = new HttpRequestMessage{
Content=content,
RequestUri = new Uri(--yourUploadURL--)
}
bool keepTracking = true; //to start and stop the tracking thread
new Task(new Action(() => { progressTracker(fileToUpload, ref keepTracking); })).Start();
var result = httpClient.SendAsync(msg).Result;
keepTracking = false; //stops the tracking thread
并将 progressTracker()
定义为
void progressTracker(FileStream streamToTrack, ref bool keepTracking)
{
int prevPos = -1;
while (keepTracking)
{
int pos = (int)Math.Round(100 * (streamToTrack.Position / (double)streamToTrack.Length));
if (pos != prevPos)
{
Console.WriteLine(pos + "%");
}
prevPos = pos;
Thread.Sleep(100); //only update progress every 100ms
}
}
这解决了我的问题。