Question

我正在使用django 1.9，我目前正在使用Windows命令提示符进行编码 - python manage.py makemigrations并出现错误：

AttributeError：＆＃39; str＆＃39;对象没有属性＆＃39;正则表达式

我尝试过编码：

url(r'^$', 'firstsite.module.views.start', name="home"),
url(r'^admin/', include(admin.site.urls)),
url(r'^$', 'django.contrib.auth.views.login', {'template_name': 'login.html'}, name='login'),
url(r'^signup/$', 'exam.views.signup', name='signup'),
url(r'^signup/submit/$', 'exam.views.signup_submit', name='signup_submit')

在urls.py中

并且错误不断出现。

这是我第一次在django编码，所以我的专业知识非常有限。先感谢您。

这是整个urls.py：

from django.conf.urls import patterns, include, url
import django
# Uncomment the next two lines to enable the admin:
from django.contrib import admin
admin.autodiscover()
from django.conf.urls.static import static
from django.conf import settings

urlpatterns = patterns('',
  # Examples:
  # url(r'^$', 'firstsite.views.home', name='home'),
  # url(r'^firstsite/', include('firstsite.foo.urls')),

  # Uncomment the admin/doc line below to enable admin documentation:
  # url(r'^admin/doc/', include('django.contrib.admindocs.urls')),

  # Uncomment the next line to enable the admin:
  #url(r'^admin/', include(admin.site.urls)),

  django.conf.urls.handler400,

  url(r'^$', 'firstsite.module.views.start', name="home"),
  url(r'^admin/', include(admin.site.urls)),
  url(r'^$', 'django.contrib.auth.views.login', {'template_name': 'login.html'}, name='login'),
  url(r'^signup/$', 'exam.views.signup', name='signup'),
  url(r'^signup/submit/$', 'exam.views.signup_submit', name='signup_submit'),
  )

Answer 1

首先，从urlpatterns的中间删除django.conf.urls.handler400。它不属于那里，并且是错误的原因。

修复错误后，您可以进行一些更改以更新Django 1.8 +的代码

将urlpatterns更改为列表，而不是使用patterns()
导入视图（或查看模块），而不是使用urls()
您对start和login次观看使用相同的正则表达式。这意味着您将无法访问登录视图。一个修复方法是将登录视图的正则表达式更改为^login/$

将它们放在一起，你会得到类似的东西：

from firstsite.module.views import start
from exam import views as exam_views
from django.contrib.auth import views as auth_views

urlpatterns = [
  url(r'^$', start, name="home"),
  url(r'^admin/', include(admin.site.urls)),
  url(r'^login/$', auth_views.login, {'template_name': 'login.html'}, name='login'),
  url(r'^signup/$', exam_views.signup, name='signup'),
  url(r'^signup/submit/$', exam_views.signup_submit, name='signup_submit'),
]

Answer 2

还要确保删除开始的空网址模式 - 迁移网址时可能会被忽略。

urlpatterns = ['', # <== this blank element ('') produces the error.
    ...
]

TL;博士

对于好奇，我通过向check_pattern_startswith_slash模块中的django.core.checks.urls方法添加警告来发现这一点：

def check_pattern_startswith_slash(pattern):
    """
    Check that the pattern does not begin with a forward slash.
    """
    if not hasattr(pattern, 'regex'):
        warning = Warning(
            "Invalid pattern '%s'" % pattern,
            id="urls.W002",
        )
        return [warning]

而且，果然，我得到了一堆像这样的警告：

?: (urls.W002) Invalid pattern ''

Answer 3

删除开始的空Url模式和也删除

django.conf.urls.handler400,

来自urls.py这将解决您的问题。

Answer 4

对于Django 2

from django.urls.resolvers import get_resolver, URLPattern, URLResolver

urls = get_resolver()

def if_none(value):
    if value:
        return value
    return ''

def print_urls(urls, parent_pattern=None):
    for url in urls.url_patterns:
        if isinstance(url, URLResolver):
            print_urls(url, if_none(parent_pattern) + if_none(str(url.pattern)))
        elif isinstance(url, URLPattern):
            print(f"{url} ({url.lookup_str})")
            print('----')
print_urls(urls)

AttributeError：＆＃39; str＆＃39;对象没有属性＆＃39; regex＆＃39; django 1.9

4 个答案:

TL;博士