Question

我有一个如下所示的列

EB.Liter+'L'+EB.CC+'cc'+'-ci'+EB.BlockType+EB.Cylinders+
         (
       EB.EngBoreIn+'x'+
        EB.EngStrokeIn+';'+
        EB.EngBoreMetric+'x'+
    EB.EngStrokeMetric
         ) as EngineBase

这个拉数据就像这样

1.3   L 1339    cc L 4 (2.87      x3.15      ;73.0      x80.0      )

但我想尝试像

这样的东西

1.3L 1339cc -ci L4 (2.87x3.15; 73.0x80.0)

如果可能，请有人建议

我尝试过这样的事情。

LTRIM(RTRIM(EB.Liter))+'L'+LTRIM(RTRIM(EB.CC))+'cc'+'-  
ci'+LTRIM(RTRIM(EB.BlockType))+LTRIM(RTRIM(EB.Cylinders))+
        + (
       LTRIM(RTRIM(EB.EngBoreIn))+'x'+
        LTRIM(RTRIM(EB.EngStrokeIn))+';'+
        LTRIM(RTRIM(EB.EngBoreMetric))+'x'+
    LTRIM(RTRIM(EB.EngStrokeMetric))
         ) as EBase

得到我的结果如下 1.3L1339cc-ciL42.87x3.15; 73.0x80.0

但正确的输出为 1.3L 1339cc -ciL4（2.87x3.15; 73.0x80.0）

Answer 1

像这样修改

LTRIM(RTRIM(EB.Liter))+'L '+LTRIM(RTRIM(EB.CC))+'cc '+'-ci'+LTRIM(RTRIM(EB.BlockType))+LTRIM(RTRIM(EB.Cylinders))+
    + '('+
    LTRIM(RTRIM(EB.EngBoreIn))+'x'+
    LTRIM(RTRIM(EB.EngStrokeIn))+'; '+
    LTRIM(RTRIM(EB.EngBoreMetric))+'x'+
    LTRIM(RTRIM(EB.EngStrokeMetric))
    +')' as EBase

Answer 2

您可以使用trim功能删除前导和尾随空格。您的查询将如下所示：

TRIM(EB.Liter) + 'L'+TRIM(EB.CC)+'cc'+'-ci'+TRIM(EB.BlockType)+TRIM(EB.Cylinders)+
(
TRIM(EB.EngBoreIn)+'x'+
TRIM(EB.EngStrokeIn)+';'+
TRIM(EB.EngBoreMetric)+'x'+
TRIM(EB.EngStrokeMetric)
) as EngineBase

两个值之间的空格

2 个答案: