Question

我试图在hive（版本1.2.1）上运行这样的查询：

DELETE  FROM employee as e WHERE  (e.id, e.name) IN ( SELECT emp.id, emp.name FROM employee_final  emp) AND e.sno = 120 ;

但是因为hive不支持这个构造所以我试过这个：

DELETE FROM employee WHERE 
id  IN (  SELECT emp.id  FROM employee_final AS  emp ) 
AND 
name IN ( SELECT emp.name  FROM employee_final AS  emp      )  
AND e.sno = 120 ;

但似乎hive有一个限制，它只支持1个子查询，我得到一个像这样的例外

错误消息：语法错误的SQL查询：];嵌套异常是org.apache.hive.service.cli.HiveSQLException：同时出错编译语句：FAILED：SemanticException [错误10249]：行 1：185不支持的SubQuery Expression'name'：只有1个SubQuery 支持表达式。

解决此问题的最有效方法是什么。

Answer 1

您可以尝试以下

通过EXISTS 我不确定这个表格是否支持HIVE中的子查询。

DELETE FROM employee as e WHERE EXISTS ( SELECT 1 FROM employee_final emp where e.id = emp.id and e.name =  emp.name ) AND e.sno = 120 ;

通过CONCAT功能

DELETE FROM employee as e WHERE concat (e.id, '#' ,e.name) IN ( SELECT concat (emp.id,'#' ,emp.name) FROM employee_final emp) AND e.sno = 120 ;

Hive：具有单个子查询的多个In-elements

1 个答案: