我的python代码中有3个词典:
self.new_port_dict = {}
#Dictionary用于存储新端口
来自curr_host self.old_port_dict = {}
#Dictionary来存储来自old_host的旧端口self.results_ports_dict = {}
#保存已更改/新添加端口的结果脚本需要比较哪个端口发生了变化,我几乎无法提供帮助:
def comp_ports(self,filename):
try:
f = open(filename)
self.prev_report = pickle.load(f) # NmapReport
for s in self.prev_report.hosts:
self.old_port_dict[s.address] = set()
for x in s.get_open_ports():
self.old_port_dict[s.address].add(x)
for s in self.report.hosts:
self.new_port_dict[s.address] = set()
for x in s.get_open_ports():
self.new_port_dict[s.address].add(x)
print "The following Host/ports were available in old scan : !!"
print `self.old_port_dict`
print "--------------------------------------------------------"
print "The following Host/ports have been added in new scan: !!"
print `self.new_port_dict`
for h in self.old_port_dict.keys():
self.results_ports_dict[h] = self.new_port_dict[h]- self.old_port_dict[h]
print "Result Change: for",h ,"->",self.results_ports_dict[h]
except Exception as l:
print l
这将输出为:
The following Host/ports were available in old scan : !!
{'172.16.0.41': set([(80, 'tcp'), (666, 'tcp')]), '172.16.0.163': set([(80, 'tcp'), (22, 'tcp')])}
--------------------------------------------------------
The following Host/ports have been added in new scan: !!
{'172.16.0.41': set([(80, 'tcp'), (22, 'tcp')]), '172.16.0.163': set([(80, 'tcp'), (22, 'tcp')])}
Result Change: for 172.16.0.41 -> set([(22, 'tcp')]) From set([(80, 'tcp'), (666, 'tcp')])
Result Change: for 172.16.0.163 -> set([]) From set([(80, 'tcp'), (22, 'tcp')])
正如你可以清楚地看到的那样,我也得到了改变后的字典。我想打印:
For "host_name" , Port changed from "port_id" to "new_port_id"
ex: For 172.16.0.41, Port changed from (666, 'tcp') to (22, 'tcp')
答案 0 :(得分:2)
根据Alex Martelli对Is there a better way to compare dictionary values
的回答你可以这样做:
#eval the differences between the 2 dict:
diff_key=[key for key in old_port_dict if old_port_dict[key]!=new_port_dict[key]]
for key in diff_key:
print "For %s, Port changed from %s to %s" %(key,old_port_dict[key],new_port_dict[key])
答案 1 :(得分:1)
我认为您不是在比较字典,而是与键对应的值。
这里的基本想法是:
主机不能总是出现在过去和现在的扫描中,并且会使用collections.defaultdict
,以确保即使在没有主机的情况下也可以直接比较值。因为缺少键的值将自动生成(空set
)
端口set
上有3个操作
&
(十字路口):查看哪些端口在扫描中保持不变(相同端口)
old - new
:查看哪些端口位于旧扫描中但不再位于新端口(已删除端口)
new - old
:查看哪些端口在新扫描中但不在旧端口(添加端口)
有几种方法可以移动代码进行优化,但我想这一点要清晰得多。
希望有所帮助
import collections
scan0 = collections.defaultdict(set, {
'172.16.0.41': set([(80, 'tcp'), (666, 'tcp')]),
'172.16.0.163': set([(80, 'tcp'), (22, 'tcp')])
})
scan1 = collections.defaultdict(set, {
'172.16.0.41': set([(80, 'tcp'), (22, 'tcp')]),
'172.16.0.163': set([(80, 'tcp'), (22, 'tcp')])
})
hosts = sorted(set(scan0.keys() + scan1.keys()))
scan_same = dict()
scan_new = dict()
scan_del = dict()
for host in hosts:
scan_same[host] = scan0[host] & scan1[host]
scan_new[host] = scan1[host] - scan0[host]
scan_del[host] = scan0[host] - scan1[host]
print()
print('-' * 10, 'Same')
for host, ports in scan_same.items():
print(host, ':')
for port in ports:
print(':::', port[0], '/', port[1])
print()
print('*' * 10, 'Added')
for host, ports in scan_new.items():
print(host, ':')
for port in ports:
print(':::', port[0], '/', port[1])
print()
print('=' * 10, 'Deleted')
for host, ports in scan_del.items():
print(host, ':')
for port in ports:
print(':::', port[0], '/', port[1])
这将输出:
---------- Same
172.16.0.163 :
::: 80 / tcp
::: 22 / tcp
172.16.0.41 :
::: 80 / tcp
*********** Added
172.16.0.163 :
172.16.0.41 :
::: 22 / tcp
========== Deleted
172.16.0.163 :
172.16.0.41 :
::: 666 / tcp
答案 2 :(得分:0)
您需要保留old_port_dict_changed = self.old_port_dict[h] - self.new_port_dict[h]
之类的其他设置,现在old_port_dict
中已更改的端口位于old_port_dict_changed
,而替换旧端口的新端口位于results_ports_dict
。这有帮助吗?