Question

我有一个包含多个词典的列表。每个字典包含7个密钥。但是，键的值是字符串和整数的混合。我想添加整数1的值。

下面是我的词典列表：
我想在所有三个词典中添加vega，theta，delta，gamma的值。

[{'option_type': 'Call', 'expiry': datetime.datetime(1993, 3, 4, 15, 20, 26), 'vega': 2, 'notional': 7840, 'delta': 1, 'strike': 520, 'theta': 5, 'gamma': 3}, {'option_type': 'Call', 'expiry': datetime.datetime(1995, 11, 14, 10, 25, 50), 'vega': 2, 'notional': 1930, 'delta': 1, 'strike': 1960, 'theta': 5, 'gamma': 3}, {'option_type': 'Put', 'expiry': datetime.datetime(1993, 3, 7, 17, 2, 30), 'vega': 2, 'notional': 5530, 'delta': 1, 'strike': 1520, 'theta': 5, 'gamma': 3}]

Answer 1

这是一个选项：

>>> import datetime
>>> data_set = [{'option_type': 'Call', 'expiry': datetime.datetime(1993, 3, 4, 15, 20, 26), 'vega': 2, 'notional': 7840, 'delta': 1, 'strike': 520, 'theta': 5, 'gamma': 3}, {'option_type': 'Call', 'expiry': datetime.datetime(1995, 11, 14, 10, 25, 50), 'vega': 2, 'notional': 1930, 'delta': 1, 'strike': 1960, 'theta': 5, 'gamma': 3}, {'option_type': 'Put', 'expiry': datetime.datetime(1993, 3, 7, 17, 2, 30), 'vega': 2, 'notional': 5530, 'delta': 1, 'strike': 1520, 'theta': 5, 'gamma': 3}]
>>> 
>>> counts = {'vega': 0, 'theta': 0, 'delta': 0, 'gamma': 0}
>>> 
>>> for data in data_set:
...     for key in counts.keys():
...         counts[key] += data[key]
... 
>>> 
>>> counts
{'gamma': 9, 'vega': 6, 'delta': 3, 'theta': 15}

Answer 2

如果您已经知道要添加其值的键，则可以在迭代项目并添加它们时创建查找列表。

这些方面的东西：

lookup_count_list = {'vega':0, 'theta':0, 'delta':0, 'gamma':0}

dict_list = [{'option_type': 'Call', 'expiry': datetime.datetime(1993, 3, 4, 15, 20, 26), 'vega': 2, 'notional': 7840, 'delta': 1, 'strike': 520, 'theta': 5, 'gamma': 3}, {'option_type': 'Call', 'expiry': datetime.datetime(1995, 11, 14, 10, 25, 50), 'vega': 2, 'notional': 1930, 'delta': 1, 'strike': 1960, 'theta': 5, 'gamma': 3}, {'option_type': 'Put', 'expiry': datetime.datetime(1993, 3, 7, 17, 2, 30), 'vega': 2, 'notional': 5530, 'delta': 1, 'strike': 1520, 'theta': 5, 'gamma': 3}]


for item in dict_list:
    for key, value in item.iteritems():
        if key in lookup_count_list.keys():
            item[key] += 1

print(lookup_count_list)

Answer 3

只需迭代并使用https://github.com/josdejong/jsoneditor方法

sum_vega = sum(i['vega'] for i in give_dict)
sum_theta = sum(i['theta'] for i in give_dict)
sum_delta = sum(i['delta'] for i in give_dict)
sum_gamma = sum(i['gamma'] for i in give_dict)

Answer 4

使用此：

import datetime

my_list=[
    {
     "vega": 2, 
     "notional": 7840, 
     "delta": 1, 
     "strike": 520, 
     "theta": 5, 
     "option_type": "Call", 
     "gamma": 3, 
     "expiry": datetime.datetime(1993, 3, 4, 15, 20, 26)
    },
    {
     "vega": 2, 
     "notional": 1930, 
     "delta": 1, 
     "strike": 1960, 
     "theta": 5, 
     "option_type": "Call", 
     "gamma": 3, 
     "expiry": datetime.datetime(1995, 11, 14, 10, 25, 50)
    },
    {
     "vega": 2, 
     "notional": 5530, 
     "delta": 1, 
     "strike": 1520, 
     "theta": 5, 
     "option_type": "Put", 
     "gamma": 3, 
     "expiry": datetime.datetime(1993, 3, 7, 17, 2, 30)
    }
]

result = {}
for dict_ in my_list:
    for key in  dict_:
        if result.has_key(key):

            if isinstance(dict_[key], int):# For integers
                result[key] += dict_[key]

            #if isinstance(dict_[key], str):# For strings
            #    result[key] = result[key] + '' + dict_[key]
            # We do not sum other types
        else:
            result[key] = dict_[key]

print result

如何在Python中添加具有相同键的字典值

4 个答案: