function CreateSuit(suit){
this.suit = suit;
this.vaule = i;
this.name = name;
}
var twoClubs = new Card ('clubs', 2, 'two of clubs');
var threeClubs = new Card ('clubs', 3, 'three of clubs');
var fourClubs = new Card ('clubs', 4, 'four of clubs');
var deck = [];
如何将这些物体放入卡座阵列?对不起,如果这是一个愚蠢的问题,我很难找到答案。
答案 0 :(得分:1)
您有几个选项,如评论中所述。
1)使用对象实例化数组:
var deck = [twoClubs, threeClubs, fourClubs];
2)将对象添加到数组中:
var deck = [];
deck.push(twoClubs);
deck.push(threeClubs);
deck.push(fourClubs);
3)你甚至可以实例化数组并同时声明对象:
var deck = [new Card ('clubs', 2, 'two of clubs'), new Card ('clubs', 3, 'three of clubs'), new Card ('clubs', 4, 'four of clubs')];
从技术上讲,这是最有效的方式(警告:这取决于浏览器/实现)。
答案 1 :(得分:1)
有几种方法可以做到这一点。您可以使用存在的值初始化数组:
var deck = [twoClubs, threeClubs, fourClubs]
或者你可以动态地将它们添加到数组中:
var deck = [];
deck.push(twoClubs);
deck.push(threeClubs);
deck.push(fourClubs);
或者您甚至可以指定数组中的位置:
var deck = [];
deck[2] = threeClubs;
deck[0] = fourClubs;
deck[1] = twoClubs
或者你可以混合搭配其中任何一个:
var deck = [threeClubs];
deck[1] = twoClubs;
deck.push(fourClubs);
答案 2 :(得分:0)
现在,您已使用其他答案中提到的任一方法在数组中添加了对象。
var deck = [twoClubs, threeClubs, fourClubs];
或
var deck = [];
deck.push(twoClubs);
deck.push(threeClubs);
deck.push(fourClubs);
您可以使用
从数组中检索并删除最后对象deck.pop(); // remove and return last object
或 您可以使用索引从特定位置检索对象
deck[1] // returns threeClubs